If earth were a ping pong what size ball would jupiter be

WILL GIVE BRAINLIEST HELP FASTWhat is the mass of Planet X? Note: The constant of universal gravity (G) equals 6.674 X 10-11 N·m

disa [49]

Answer:

Explanation:

Centripetal acceleration's equation is:

$a_c=\frac{v^2}{r}$ where v is the velocity of the object (moon II) and r is the radius. We have the radius, but we don't have the velocity, and we can't solve for acceleration until we do have it. Assuming moon II is a circle, or close enough to be called a circle, it has a circumference.

C = 2πr. If we can find the circumference of the circle, we can plug in the orbital period for the time, the circumference for the distance, and solve for velocity in d = rt. So let's do that and see what happens.

C = 2(3.14)(9.0 × 10⁷) and

C = d = 5.7 × 10⁸. Plugging in and solving for v:

$5.7*10^8=v(3.0*10^5)$ and

v = 1.9 × 10³. That is the velocity we can use in the centripetal acceleration equation.

$a_c=\frac{(1.9*10^3)^2}{9.0*10^7}$ and

$a_c=.040\frac{m}{s^2}$

These are fun!

8 0

3 years ago

Question 1

Dominik [7]

Answer:

a. All the laboratory equipment given are very basic equipment used in all the laboratories. Name of each equipment is as follows:

V refers to the tape measure.
W refers to dropper.
X refers to an inoculating loop.
Y refers to a stopwatch.
Z refers to the microscope.

b. Use of each laboratory equipment identified is:

Tape measures (V) is used to measure the length of objects or distance in a laboratory.
Dropper (W) is used to measure unit of drop required to dispensed as one drop or several drops in any experiment.
Inoculating loop (X) is used by microbiologists to cultivate microbes on plates and retrieving an inoculum from a culture of microorganisms.
Stopwatch (Y) is used to measure the time of any experiment.
Microscope (Z) is used to magnify an object to look at it in detail.

3 0

3 years ago

Which image represents the force on a positively charged particle caused by an approaching magnet?

Amanda [17]

Answer:

Image B represents the force on a positively charged particle caused by an approaching magnet.

Explanation:

The most fundamental law of magnetism is that like shafts repulse each other and dissimilar to posts pull in one another; this can without much of a stretch be seen by endeavoring to put like posts of two magnets together. Further attractive impacts additionally exist. On the off chance that a bar magnet is cut into two pieces, the pieces become singular magnets with inverse shafts. Also, pounding, warming or winding of the magnets can demagnetize them, on the grounds that such dealing with separates the direct game plan of the particles. A last law of magnetism alludes to maintenance; a long bar magnet will hold its magnetism longer than a short bar magnet. The domain theory of magnetism expresses that every single enormous magnet involve littler attractive districts, or domains. The attractive character of domains originates from the nearness of significantly littler units, called dipoles. Iotas are masterminded in such a manner in many materials that the attractive direction of one electron counteracts the direction of another; in any case, ferromagnetic substances, for example, iron are unique. The nuclear cosmetics of these substances is with the end goal that littler gatherings of particles unite as one into zones called domains; in these, all the electrons have the equivalent attractive direction.

4 0

3 years ago

A toaster using a Nichrome heating element operates on 120 V. When it is switched on at 28 ∘С, the heating element carries an in

sukhopar [10]

Answer:

The final temperature of the element = 262.67°C

The power dissipated in the heating element initially = 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A = 147.60 W

Explanation:

Our given parameters include;

A Nichrome heating element operates on 120 V.

Voltage (V) = 120V

Initial Current (I₁) = 1.36 A

Initial Temperature (T₁) = 28°C

Final Current (I₂) = 1.23 A

Final Temperature (T₂) = unknown ????

Temperature dependencies of resistance is given by:

$R_{T(2)}=R_1[1+\alpha (T_2-T_1)]$ ---------------------- (1)

in which R₁ is the resistance at temperature T₁

$R_{T(2)$ is the resistance at temperature T₂

Given that V= IR

R = $\frac{V}{I}$

Therefore, the resistance at temperature 28°C is;

$R_{28}= \frac{120V}{1.36A}$

= 88.24Ω

$R_{T(2)$ = $\frac{120V}{1.23A}$

= 97.56Ω

From (1) above;

$R_{T(2)}=R_1[1+\alpha (T_2-T_1)]$

97.56 = 88.24 [ 1 + 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)]

$\frac{97.56}{88.24}= 1+(4.5*10^{-4})(T-28^0C)$

1.1056 - 1 = 4.5×10⁻⁴(°C)⁻¹(T₂-28°C)

0.1056 = 4.5×10⁻⁴(T₂-28°C)

$\frac{0.1056}{4.5*10^{-4}}= T-28^0C$

T - 28° C = 234.67

T = 234.67 + 28° C

T = 262.67 ° C

(b)

What is the power dissipated in the heating element initially and when the current reaches 1.23 A

The power dissipated in the heating element initially can be calculated as:

P = I²₁R₂₈

P = (1.36A)²(88.24Ω)

P = 163.209 W

P ≅ 163.21 W

The power dissipated in the heating element when the current reaches 1.23 A can be calculated as:

$P= I^2_2R_{T^0C$

P = (1.23)²(97.56Ω)

P = 147.598524

P ≅ 147.60 W

6 0

3 years ago

1. What are the units of : pressure, force , area

White raven [17]

Pressure- Pascal( $N/m^2$ )

Force- Newton

Area- $m^2$ (Square metre)

<u>Explanation:</u>

Pressure is force continuous force applied to an object. The applied force is always perpendicular to the surface of the object.
Force is a push or pulls on an object by an external body where it changes its state from rest to motion.
Force is said to have both magnitude and direction.
Area is the portion that shows the scale of a 2D form or configuration in the level. The covering area is its analog on the 2D surface of a 3D object.

6 0

3 years ago