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natka813 [3]
4 years ago
10

Convert 100 millimeters to meters

Physics
1 answer:
drek231 [11]4 years ago
3 0

100 millimeters equals 0.1 meters.

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Suppose there is a bright fringe at P Would this bright fringe move closer to O, move further away, or be unchanged, t 1.5 marks
fiasKO [112]

Answer:

Explanation:

The distance of a fringe from centre is proportional to wavelength of light

and inversely proportional to separation of slits. The expression for distance x is given by

x = nλ D / d

where λ is wave length , D is screen distance and d is slit separation.

So first option only is correct because

1 ) the wavelength of blue light is less than that of red

2) Intensity of light does not affect distance of fringe from the centre.

3.

Diffraction symbolises bending of light around sharp edges like slits or boundaries of opaque objects etc.Due to this reason , we do not observe sharp boundary of shadow of an object. Instead around the boundary of shadow, we observe bands of bright and dark color which are also called fringes.

The phenomena of diffraction is explained by wave theory of light.

3 0
3 years ago
Calculator
denpristay [2]

Answer:

25

Explanation:

By Using Pythagoras Theorem,

h^2=p^2+b^2

or, x^2=(24)^2+7^2

or, x^2=576+49

or, x^2=625

or, x=√625

•°• x=25

5 0
3 years ago
Many counties in Florida missed many school days in the fall of 2004 due to hurricanes that year. A solution for how to make up
Ivenika [448]

Answer:

108 extended days

Explanation:

Regular school hours a day = 6 hr

No. of school days to make up by extending the  regular hours = 3 days

Amount of time added to the regular hours of school = 10 min

No. of extended school days to make up the 3 school days by following the above mentioned criteria be x.

Time of school hours in 3 days = 3\times 6= 18\,hr\,\,\,\, ;or\,\,\, (18\times 60)\,minutes

\therefore x=\frac{18\times 60}{10}

x=108\,\,days are required to make up 3 days of school having 6 hours of regular timing with 10 minutes of add-on time each day.

4 0
4 years ago
The IMA is always smaller than the AMA.<br><br> True<br> False
VMariaS [17]
Best answer must be false. Because the IMA it doesn't have always stay smaller than the AMA. Hope it helped you!
6 0
4 years ago
3) Find the missing parts of the triangle (angle and/or sides).<br>​
oee [108]

Answer:

44.4°

Explanation:

Use SOH-CAH-TOA.

Sine = Opposite / Hypotenuse

Cosine = Adjacent / Hypotenuse

Tangent = Opposite / Adjacent

You're given an unknown angle, the adjacent side to that angle, and the hypotenuse.  So use cosine.

Cosine = Adjacent / Hypotenuse

cos A = 10 / 14

A = cos⁻¹(5/7)

A ≈ 44.4°

8 0
3 years ago
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