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natka813 [3]
4 years ago
10

Convert 100 millimeters to meters

Physics
1 answer:
drek231 [11]4 years ago
3 0

100 millimeters equals 0.1 meters.

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Mary pushes a crate by applying force of 18 newtons. Unable to push it alone, she gets help from her friend, Anne. Together they
maw [93]
 <span>This problem is relatively simple, in order to solve this problem the only formula you need to know is the formula for friction, which is: 

Ff = UsN 

where Us is the coefficient of static friction and N is the normal force. 

In order to get the crate moving you must first apply enough force to overcome the static friction: 

Fapplied = Ff 

Since Fapplied = 43 Newtons: 

Fapplied = Ff = 43 = UsN 

and it was given that Us = 0.11, so all you have to do is isolate N by dividing both sides by 0.11 

43/0.11 = N = 390.9 which is approximately 391 or C. 3.9x10^2</span>
7 0
3 years ago
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Solve the equation. 5x-5=10x+2
Veronika [31]

Answer:

x = - 1.4

Explanation:

-5=10x+2-5x     (subtract 5x from both sides)

-5=5x+2     (simplify)

-5-2=5x     (subtract 2 from both sides)

-7=5x      (simplify)

x=-7/5     (divide both sides by 5)

x=-1.4    (simplify)

i would really appreciate getting a brainliest. anyways i hope this helped and have a great rest of your day/night!! :)

8 0
3 years ago
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Why is the following situation impossible? A skater glides along a circular path. She defines a certain point on the circle as h
Arturiano [62]

Answer:

A skater glides along a circular path. She defines a certain point on the circle as her origin. Later on, she passes through a point at which the distance she has traveled along the path from the origin is smaller than the magnitude of her displacement vector from the origin.

So here in circular motion of the skater we can see that the total path length of the skater is along the arc of the circle while we can say that displacement is defined as the shortest distance between initial and final position of the object.

So it is not possible in any circle that arc-length is less than the chord joining the two points on the circle

As we know that arc length is given as

L = R\theta

length of chord is given as

L_c = 2Rsin(\frac{\theta}{2})

so here

L > L_c

R\theta > 2R sin(\frac{\theta}{2})

so we have

\frac{\theta}{2} > sin(\frac{\theta}{2})

6 0
3 years ago
A 39.3 g glass thermometer reads 22.0oC before it
ratelena [41]

Answer:

44.85C

Explanation:

Let the specific heat of glass thermometer be 0.84 J/g°C

Let the specific heat of water be 4.186 j/g °C

Let the water density be 1kg/L

136 mL of water = 0.136L of water = 0.136 kg of water = 136 g of water

Since the change of temperature on the glass thermometer is 43.6 - 22 = 21.6 C. We can then calculate the heat energy absorbed to it:

E = m_gc_g \Delta T = 39.3 * 0.84 * 21.6 = 713.06 J

Assume no energy is lost to outside, by the law of energy conservation, this heat energy would come from water

E = m_wc_w(T - T_w) = 713.06

136*4.186(T - 43.6) = 713.06

T - 43.6 = \frac{713.06}{136*4.186} = 1.25

T = 1.25 + 43.6 = 44.85C

6 0
3 years ago
Calculate ∆U for each of the following cases:
dusya [7]

Answer:

Q=+100kj,w=-15kj,Q=100kj,w=-62kj

Explanation:

when energy is exerted into a system work done is equal to zero .hence the system does work to the surrounding.

3 0
2 years ago
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