Answer:
Explanation:
rate of reaction
= -ve change in pressure of ethanol / time
= - (250 -237 )/100 = - 13 / 100 torr/s
= - 0.13 torr/s
next
- (237 - 224 )/100 = - 13 / 100 torr/s
= - .13 torr/s
next
- (224 - 211 )/100 = - 13 / 100 torr/s
= - .13 torr/s
so on
So rate of reaction is constant and it does not depend upon concentration or pressure of reactant .
So order of reaction is zero.
rate of reaction =K [C₂H₅OH]⁰
K is rate constant
K = .13 torr/s
In 900 s decrease in pressure
= 900 x .13 = 117
So after 900s , pressure of ethanol will be
250 - 117 = 133 torr
Answer : Option A) Translation
Explanation : A composition of reflections over parallel lines is the same as a <u>Translation.</u>
To identify if the composition of reflections over parallel lines are same as translation or not?
We can check using a picture of some shape in the plane. Place the picture on the right side of two vertical parallel. Now, we can see the reflected the shape over the nearest parallel line, then check the reflection over the other parallel line. We see that the shape winds up in the same orientation, like it was just shifted over to the right. Hence, it is translation.
5 electrons
Boron atomic number 5 has five electrons in its ground state.
Commonly Boron will lose 3 electrons leaving 2 electrons in its most common ionic form.
Explanation:
The atomic number gives the number of protons. Protons which have a positive charge are balanced by an equal number of electrons in a neutral atom.
Boron number 5 has five protons and therefore as a neutral atom also has five electrons.
Boron has an electron configuration of
1s22s22p1
The most stable electron configuration for Boron is
1s2
+ 3 charges. By losing three electrons Boron can achieve the stable electron structure of Helium
Brainliest? :D
Answer:
<u>84.00 kPa = 630.084 torr</u>
Formula for kPa to torr: For an approximate result, multiply the pressure value by 7.501. <em><u>84* 7.501</u></em>
<u>84.00 kPa = 0.831683168 atm</u>
Formula for kPa to atm: for an approximate result, divide the pressure value by 101. <em><u>84/101</u></em>