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scoundrel [369]
3 years ago
9

After dinner, Joanne did not put the leftover casserole away until after watching her favorite television show. What is the long

est time it should be left out at room temperature?
Physics
1 answer:
Sever21 [200]3 years ago
7 0

Answer:

At most 2 hours

Explanation:

According to my research of various health departments it is said that cooked food should not be left out in room temperature for more than 2 hours, assuming that room temperature is between 40°F and 140°F. This is because after 2 hours bacteria starts to grow at an increased rate and can have various health effects on the person consuming the food. Therefore food is best wrapped and placed in the refrigerator.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

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An electromagnet is created using a battery, an insulated copper wire and an iron nail. The wire is wrapped around the nail 30 t
Veseljchak [2.6K]

Answer:

Explanation:

If one assume that each turn is like a strand of electromagnet, which can then be added up. Therefore, increase in the number of turns will yield to increase in the magnetic strength. Also if the current increases, then there will be increase in the magnetic field strength.

From Ohm's law

V = IR

I = V/R

That is a direct increase in voltage will lead to increase in current.

Increase the voltage of the battery and increases the number of turns of the coil. Will suit the situation

4 0
2 years ago
A hot-air balloon of diameter 12 mm rises vertically at a constant speed of 14 m/s. A passenger accidentally drops his camera fr
fgiga [73]

Answer:

<em>The balloon is 66.62 m high</em>

Explanation:

<u>Combined Motion </u>

The problem has a combination of constant-speed motion and vertical launch. The hot-air balloon is rising at a constant speed of 14 m/s. When the camera is dropped, it initially has the same speed as the balloon (vo=14 m/s). The camera has an upward movement for some time until it runs out of speed. Then, it falls to the ground. The height of an object that was launched from an initial height yo and speed vo is

\displaystyle y=y_o+v_o\ t-\frac{g\ t^2}{2}

The values are

\displaystyle y_o=15\ m

\displaystyle v_o=14\ m/s

We must find the values of t such that the height of the camera is 0 (when it hits the ground)

\displaystyle y=0

\displaystyle y_o+v_o\ t-\frac{g\ t^2}{2}=0

Multiplying by 2

\displaystyle 2y_o+2v_ot-gt^2=0

Clearing the coefficient of t^2

\displaystyle t^2-\frac{2\ V_o}{g}\ t-\frac{2\ y_o}{g}=0

Plugging in the given values, we reach to a second-degree equation

\displaystyle t^2-2.857t-3.061=0

The equation has two roots, but we only keep the positive root

\displaystyle \boxed {t=3.69\ s}

Once we know the time of flight of the camera, we use it to know the height of the balloon. The balloon has a constant speed vr and it already was 15 m high, thus the new height is

\displaystyle Y_r=15+V_r.t

\displaystyle Y_r=15+14\times3.69

\displaystyle \boxed{Y_r=66.62\ m}

3 0
2 years ago
Work done can be describe as?​
Neko [114]

Explanation:

In physics, work is the energy transferred to or from an object via the application of force along a displacement. In its simplest form, it is often represented as the product of force and displacement. A force is said to do positive work if (when applied) it has a component in the direction of the displacement of the point of application. A force does negative work if it has a component opposite to the direction of the displacement at the point of application of the force.

Quick Facts: Common symbols, SI unit ...

Work

A baseball pitcher does positive work on the ball by applying a force to it over the distance it moves while in his grip.

Common symbols

W

SI unit

joule (J)

Other units

Foot-pound, Erg

In SI base units

1 kg⋅m2⋅s−2

Derivations from

other quantities

W = F ⋅ s

W = τ θ

Dimension

M L2 T−2

Close

For example, when a ball is held above the ground and then dropped, the work done by the gravitational force on the ball as it falls is equal to the weight of the ball (a force) multiplied by the distance to the ground (a displacement). When the force F is constant and the angle between the force and the displacement s is θ, then the work done is given by:

{\displaystyle W=Fs\cos {\theta }}{\displaystyle W=Fs\cos {\theta }}

Work is a scalar quantity, so it has only magnitude and no direction. Work transfers energy from one place to another, or one form to another. The SI unit of work is the joule (J), the same unit as for energy.

4 0
3 years ago
Which layer of the sun's atmosphere are you looking at when you look at me in image of the Sun
Hitman42 [59]
The answer is Photosphere.  The photosphere is the lowest layer<span> of the </span>solar<span> atmosphere. It is essentially the </span>solar<span> "surface" that </span>we see<span> when </span>we look<span> at the </span>Sun in "white" light.  It is <span>like a glowing fog, so at a distance, it </span>looks<span> solid, the same way a cloud looks solid from a distance.</span>
7 0
3 years ago
Can a vector have a component greater than its magnitude
galina1969 [7]

Answer:

NO

Explanation:

The components of a vector can not have a magnitude greater than the vector itself.The magnitude of a component is always lesser than vector because the magnitude is a product of the vector and cos Ф where the value of cos Ф , x,  is -1<x<1. Additionally, applying the Pythagorean relationship, you expect the sum of squares of the components to equal the square of the magnitude of the vectors.However, there is a situation where a component of a vector has a magnitude which equals the magnitude of the vector.

6 0
3 years ago
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