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4 years ago

What is the electric potential 16.0 cm from a 4.00 μC point charge?

Physics

1 answer:

AveGali [126]4 years ago

7 0

Answer:

the potential at a distance of 16 cm from the charge $4\mu C$ will be 225000 volt

Explanation:

We have given charge $q=4\mu C=4\times 10^{-6}C$

Distance between the charge r = 16 cm = 0.16 m

Electric potential is given by $V=\frac{1}{4\pi \varepsilon _0}\frac{q}{r}=\frac{Kq}{r}$ , here K is constant which value is $9\times 10^9Nm^2/C^2$

So potential $V=\frac{9\times 10^9\times 4\times 10^{-6}}{0.16}=225000volt$

So the potential at a distance of 16 cm from the charge $4\mu C$ will be 225000 volt

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In an experiment,the group that is exposed to the variable to be tested is called

bagirrra123 [75]

Answer:

The group that is exposed to the variable to be tested is called as experimental group.

Explanation:

An experiment consists of two kinds of group. They are experimental group and control group. The working of control group and experimental group are mostly same except that the variables will be changed in experimental group, while it is kept constant in control group. So at the end of experiments, the results from control group and experimental group are compared and the final outcome has been derived. So the given statement where the group is exposed to the variable to be tested or the independent variable is called as experimental group.

4 0

3 years ago

A gamma-ray photon produces an electron and a positron, each with a kinetic energy of 261 keV . h=6.626×10−34J⋅s, c=2.998×108m/s

ddd [48]

Answer:

The energy and the wavelength of the photon are 1.546 MeV and $8.036\times10^{-13}\ m$ .

Explanation:

Given that,

Kinetic energy = 261 KeV

Planck's constant $h = 6.626\times10^{−34}\ J.s$

Speed of light $c=2.998\times10^{8}\ m/s$

Mass of electron $m_{e}=9.109\times10^{-31}\ kg$

Charge $q=1.602\times10^{-19}\ C$

(A). We need to calculate the energy of the photon

Using formula of rest mass energy

$E=m_{0}c^2$

$E=9.109\times10^{-31}\times(3\times10^{8})^2$

$E=8.198\times10^{-14}\ J$

Energy in eV

$E=\dfrac{8.198\times10^{-14}}{1.6\times10^{-19}}$

$E=512375\ eV$

$E=0.512\ MeV$

The total energy of photon

$TE=2(E+K.E)$

$TE=2(0.512+0.261)$

$TE=1.546\ MeV$

(B). We need to calculate the wavelength of the photon

Using formula of wavelength

$\lambda=\dfrac{hc}{E}$

Put the value into the formula

$\lambda=\dfrac{6.626\times10^{−34}\times3\times10^{8}}{1.546\times10^{6}\times1.6\times10^{-19}}$

$\lambda=8.036\times10^{-13}\ m$

Hence, The energy and the wavelength of the photon are 1.546 MeV and $8.036\times10^{-13}\ m$ .

7 0

3 years ago

A circular loop of wire with 15 turns, radius 0.129 m and resistance 0.251 Ohms is connected to a 16.7 V power supply. The magne

Licemer1 [7]

The magnetic field at the center of the circular loop is 3.24 x 10⁻⁴ T.

<h3>Current in the wire</h3>

The current in the wire is calculated as follows;

V = IR

I = V/R

I = 16.7/0.251

I = 66.53 A

<h3>Magnetic field at the center of the loop</h3>

The magnetic field at the center of the circular loop is calculated as follows;

$B = \frac{\mu_0 I}{2R} \\\\B = \frac{4\pi \times 10^{-7} \times66.53 }{2\times 0.129} \\\\B = 3.24 \times 10^{-4} \ T$

Learn more about magnetic field here: brainly.com/question/7802337

3 0

2 years ago

What is the thermal energy of an object?

mr Goodwill [35]

The thermal energy of an object is the energy contained in the motion and vibration of its molecules. Thermal energy is measured through temperature. The energy contained in the small motions of the object's molecules can be broken up into a combination of microscopic kinetic energy and potential energy.

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3 years ago

Historically, rhenium was alloyed to the tungsten in the filament of valve tubes to increase electron emission. What is the majo

ziro4ka [17]

Answer:

usually x-ray tube filaments are devices that limit the current flow i.e. current cannot easily pass through them or we can say that they are current limited devices. So to allow fine electron transmission control by filament heating current, rhenium must not be used in x-ray tube filaments.

8 0

3 years ago