Question

What is the electric potential 16.0 cm from a 4.00 μC point charge?

Answer 1

Answer:

the potential at a distance of 16 cm from the charge $4\mu C$ will be 225000 volt

Explanation:

We have given charge $q=4\mu C=4\times 10^{-6}C$

Distance between the charge r = 16 cm = 0.16 m

Electric potential is given by $V=\frac{1}{4\pi \varepsilon _0}\frac{q}{r}=\frac{Kq}{r}$, here K  is constant which value is $9\times 10^9Nm^2/C^2$

So potential $V=\frac{9\times 10^9\times 4\times 10^{-6}}{0.16}=225000volt$

So the potential at a distance of 16 cm from the charge $4\mu C$ will be 225000 volt