What is the electric potential 16.0 cm from a 4.00 μC point charge?
1 answer:
Answer:
the potential at a distance of 16 cm from the charge will be 225000 volt
Explanation:
We have given charge
Distance between the charge r = 16 cm = 0.16 m
Electric potential is given by , here K is constant which value is
So potential
So the potential at a distance of 16 cm from the charge will be 225000 volt
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Answer:
a)
b) mg>N
c)
d)
Explanation:
In order to solve part a) of the problem, we can start by drawing a free body diagram of the presented situation. (see attached picture).
In this case, we know the centripetal acceleration is given by the following formula:
where:
we know the period of rotation of the earth is about 24 hours, so:
so we can now find the angular speed:
So the centripetal acceleration will be:
which yields:
b)
In order to answer part b, we must draw a free body diagram of us sitting on a chair. (See attached picture.)
So we can do a sum of forces in equilibrium:
so we get that:
and solve for the normal force:
In this case, we can clearly see that:
therefore mg>N
This is because the centripetal acceleration is pulling us upwards, that will make the magnitude of the normal force smaller than the product of the mass times the acceleration of gravity.
c)
So let's calculate our weight and normal force:
Let's say we weight a total of 60kg, so:
and let's calculate the normal force:
N=586.58N
so now we can calculate the percentage change:
so we get:
which is a really small change.
d) In order to find this acceleration, we need to start by calculating the radius of rotation at that point of earth. (See attached picture).
There, we can see that the radius can be found by using the cos function:
In this case:
so we can solve for r, so we get:
in this case we'll use the average radius of earch which is 6,371 km, so we get:
which yields:
r=4,551.91 km
and now we can calculate the acceleration at that point:
