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AveGali [126]
4 years ago
14

What is the electric potential 16.0 cm from a 4.00 μC point charge?

Physics
1 answer:
AveGali [126]4 years ago
7 0

Answer:

the potential at a distance of 16 cm from the charge 4\mu C will be 225000 volt

Explanation:

We have given charge q=4\mu C=4\times 10^{-6}C

Distance between the charge r = 16 cm = 0.16 m

Electric potential is given by V=\frac{1}{4\pi \varepsilon _0}\frac{q}{r}=\frac{Kq}{r}, here K  is constant which value is 9\times 10^9Nm^2/C^2

So potential V=\frac{9\times 10^9\times 4\times 10^{-6}}{0.16}=225000volt

So the potential at a distance of 16 cm from the charge 4\mu C will be 225000 volt

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A proposed communication satellite would revolve around the earth in a circular orbit in the equatorial plane at a height of 358
aleksandr82 [10.1K]

Answer:

Period is 86811.5 seconds.

Explanation:

{ \boxed{ \bf{T {}^{2} =  (\frac{4 {\pi}^{2} }{GM}) {r}^{3}   }}}

{ \tt{T {}^{2}  =  \frac{4 {(3.14)}^{2} }{(6.6 \times  {10}^{ - 11} ) \times (5.98 \times  {10}^{24} )} \times  {((35880\times  {10}^{3}) } + (6370 \times  {10}^{3} )) {}^{3}   }} \\  \\ { \tt{T {}^{2}  =  7.54 \times {10}^{9} }} \\ { \tt{T =  \sqrt{7.54 \times  {10}^{9} } }} \\ { \tt{T = 86811.5 \: seconds}}

6 0
3 years ago
Radio waves travel at a speed of 300,000,000 m/s. WFNX broadcasts radio waves at a
yKpoI14uk [10]

Answer:

Wavelength, \lambda=2.94\ m

Explanation:

It is given that,

Speed of radio waves is v=3\times 10^8\ m/s

Frequency of radio waves is f = 101,700,000 Hz

We need to find the wavelength of WFNX’s radio waves. The relation between wavelength, frequency and speed of a wave is given by :

v=f\lambda

\lambda is wavelength

\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{3\times 10^8}{101,700,000}\\\\\lambda=2.94\ m

So, the wavelength of WFNX’s radio waves is 2.94 m.

3 0
4 years ago
Will award brainliest and upvote if you can help answer! ​
erica [24]

Answer:

Omqnp

Explanation:

I have done this before and got it correct

7 0
3 years ago
When a wire within a closed circuit is coiled upon a nail, the nail will _______.
Natali5045456 [20]

when wire is coiled upon a nail then it will posses magnetic characteristics

This is due to the coiled shape it will behave like a solenoid and the magnetic field of solenoid is given as

B = \mu_o ni

so here when wire is coiled up on a nail then due to the magnetic field of the coil the nail will attain magnetic characteristic.

so correct answer will be

<em>Possess magnetic properties </em>

5 0
3 years ago
Read 2 more answers
One of the main factors driving improvements in the cost and complexity of integrated circuits (ICs) is improvements in photolit
nika2105 [10]

Answer:

0.000003782 m

0.000001891 m

0.000001197125 m

Explanation:

\lambda = Wavelength = 248 nm

D = Diameter of beam = 1 cm

f = Focal length = 0.625 cm

The angle is given by

\theta=\dfrac{1.22\lambda}{D}

The width is given by

d=2\theta f\\\Rightarrow d=2\dfrac{1.22\lambda f}{D}\\\Rightarrow d=2\dfrac{1.22\times 248\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.000003782\ m

The required width is 0.000003782 m

Minimum resolvable line separation is given by

\dfrac{0.000003782}{2}=0.000001891\ m

The minimum resolvable line separation between adjacent lines is 0.000001891 m

when \lambda=157\ nm

d=2\dfrac{1.22\times 157\times 10^{-9}\times 6.25\times 10^{-2}}{1\times 10^{-2}}\\\Rightarrow d=0.00000239425\ m

The new minimum resolvable line separation between adjacent lines is

\dfrac{0.00000239425}{2}=0.000001197125\ m

6 0
3 years ago
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