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just olya [345]
3 years ago
8

Which use of iron is due to its chemical properties?

Chemistry
2 answers:
tangare [24]3 years ago
5 0

Answer:

A is the correct answer

Explanation:

if I'm wrong I'm very sorry

saw5 [17]3 years ago
4 0
The answer is A I believe
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A sample of neon occupies a volume of 478 mL at STP. What will be the volume of the neon when the pressure is reduced to 93.3 kP
Andre45 [30]

The volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

Explanation:

The kinetic theory of gases is mostly based on Boyle's law. From the Boyle's law, the pressure experienced by any gas molecules is inversely proportional to volume of the gas molecules. Also this inverse relation is obeyed if and only if the number of moles and temperature of the gas molecules remained constant.

So,P=\frac{1}{V}

So if there is a change in pressure then there will be inverse change in volume. That means if there is decrease in the pressure of gas molecules then there will be increase in the volume and vice versa.

So the Boyle's law is combined as P_{1} V_{1} = P_{2} V_{2}

As here the initial pressure or P_{1} is 1 atm or 101.3 kPa and the initial volume is 478 mL. Similarly, the final pressure is 93.3 kPa and the final volume will be

101.3*10^{3}*478*10^{-3}  = 93.3*10^{3} * V_{2}

V_{2} = 519 mL

So, the volume of neon when the pressure is reduced to 93.3 kPa is 519 mL.

5 0
3 years ago
A tire at 21ÁC has a pressure of 0.82 atm. Its temperature decreases to _3.5ÁC. If there is no volume change in the tire, what i
amid [387]
Volumen = constant => P/T = constant

T1 = 21°C + 273.15 = 294.15 k
P1 = 0.82 atm

T2 = - 3.5°C + 273.15 = 269.65 k
P2 = ?

P2 / 269.65k = 0.82atm / 294.15k

P2 = [0.82atm / 294.15k] * 269.65kg = 0.75 atm
3 0
4 years ago
How could you use two beakers distilled water two hot plates two thermometers and salt to test if adding salt affects the boilin
ICE Princess25 [194]
You are given two beakers, distilled water, two hot plates, two thermometers and salt. These materials are enough in order to test the effect of salt in the boiling point water. To do this, you set up two beakers. In one of the beakers, you add pure distilled water and nothing else. For the other beaker, you put a solution of salt and water. You place these beakers on separate hot plates and place inside the beakers the thermometers. You heat these substances until they boil and then you measure the boiling points of the substances. You would observe that the boiling point of the solution would have a higher boiling point than the pure liquid.
3 0
4 years ago
Arrange the colors of visible light, green, red, and blue, in order of increasing wavelength.
lukranit [14]

Answer: The increasing wavelength of colors:

Red > Green > Blue

Explanation:

Wavelength: This is the property of wave which includes the distance between two consecutive crests or trough. This is denoted by the Greek letter Lambda and it is found by dividing the velocity of the wave with its frequency.

Wavelength of colours are

Violet: 400 - 420 nm

Indigo: 420 - 440 nm

Blue: 440 - 490 nm

Green: 490 - 570 nm

Yellow: 570 - 585 nm

Orange: 585 - 620 nm

Red: 620 - 780 nm

8 0
3 years ago
Calculate the density of air at 100 Deg C and 1 bar abs. Use the Ideal Gas Law for your calculation and give answer in kg/m3. Us
madam [21]

Answer:

d=0.92\frac{kg}{m^{3}}

Explanation:

Using the Ideal Gas Law we have PV=nRT and the number of moles n could be expressed as n=\frac{m}{M}, where m is the mass and M is the molar mass.

Now, replacing the number of moles in the equation for the ideal gass law:

PV=\frac{m}{M}RT

If we pass the V to divide:

P=\frac{m}{V}\frac{RT}{M}

As the density is expressed as d=\frac{m}{V}, we have:

P=d\frac{RT}{M}

Solving for the density:

d=\frac{PM}{RT}

Then we need to convert the units to the S.I.:

T=100^{o}C+273.15

T=373.15K

P=1bar*\frac{0.98atm}{1bar}

P=0.98atm

M=28.9\frac{kg}{kmol}*\frac{1kmol}{1000mol}

M=0.0289\frac{kg}{mol}

Finally we replace the values:

d=\frac{(0.98atm)(0.0289\frac{kg}{mol})}{(0.082\frac{atm.L}{mol.K})(373.15K)}

d=9.2*10^{-4}\frac{kg}{L}

d=9.2*10^{-4}\frac{kg}{L}*\frac{1L}{0.001m^{3}}

d=0.92\frac{kg}{m^{3}}

5 0
4 years ago
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