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Licemer1 [7]
4 years ago
10

The hydronium ion concentration for an aqueous solution in which the hydroxide ion concentration is 1 x 10-10 is

Chemistry
1 answer:
Mashcka [7]4 years ago
8 0

Answer:

First option is the right choice.

Explanation:

[H_3O^+]=1\times 10^{-4}\:M

Best Regards!

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What kind of mixture is a solution? A suspension? A colloid?
kompoz [17]
Solution = homogeneous mixture
Suspension = heterogeneous mixture
Colloid = homogeneous mixure
3 0
3 years ago
The blue colour of the sky results from the scattering of sunlight by air molecules. Blue light has a frequency if about 7.5*10^
erastovalidia [21]

Answer: The energy of a mole of photon associated with this frequency is 49.5\times 10^{-20}J

Explanation:

The energy and frequency are related by :

E=N\times h\times \nu

E = energy of photon

N = number of moles = 1

h = planks constant = 6.6\times 10^{-34}Js

\nu = frequency = 7.5\times 10^{14}Hz

E=1\times 6.6\times 10^{-34}Js\times 7.5\times 10^{14}s^{-1}=49.5\times 10^{-20}J

The energy of a mole of photon associated with this frequency is 49.5\times 10^{-20}J

6 0
3 years ago
Consider this reaction: Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g).
iragen [17]
Option are as follow,

A. temperature, concentration and surface area 
<span>B. temperature, and concentration only </span>
<span>C. concentration and surface area only </span>
<span>D. temperature and surface area only
</span>
Answer:
           Option-<span>A. Temperature, Concentration and Surface area
</span>
Explanation:

1) Increasing Temperature:
                                              Increase in temperature increases the Kinetic energy of molecules. This results in increase in the velocity and rate of collisions between reactants. Hence, greater the number of collisions between reactants per time greater will be the probability of formation of product per unit time.

2) Increasing Concentration
                                            Increase in concentration results in increase in number of particles of reactants per unit area, hence collision rate increases resulting in rate of reaction.

3) Increasing Surface Area
                                             Grinding of Zn results in the increase of surface area of Zinc. So greater the surface area greater is the exposure of Zinc metal to HCl molecules, hence the rate of formation of product increases.
5 0
3 years ago
In the laboratory, hydrogen gas is usually made by the following reaction: Zn(s) + 2 HCl(aq) → H2(g) + ZnCl2(aq) How many liters
IrinaK [193]

<u>Answer:</u> The volume of hydrogen gas collected over water is 2.13 L

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Given mass of zinc = 5.566 g

Molar mass of zinc = 65.4 g/mol

Putting values in above equation, we get:

\text{Moles of zinc}=\frac{5.566g}{65.4g/mol}=0.0851mol

For the given chemical reaction:

Zn(s)+2HCl(aq.)\rightarrow H_2(g)+ZnCl_2(aq.)

As, HCl is present in excess. So, it is considered as an excess reagent.

Zinc is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of zinc produces 1 mole of hydrogen gas.

So, 0.0851 moles of zinc will produce = \frac{1}[1}\times 0.0851=0.0851mol of hydrogen gas

To calculate the volume of hydrogen gas, we use ideal gas equation, which is:

PV = nRT

where,

P = Pressure of hydrogen gas = Total atmospheric pressure - vapor pressure of water = (752 - 18.65) mmHg = 733.35 mmHg

V = Volume of the hydrogen gas

n = number of moles of gas = 0.0851 moles

R = Gas constant = 62.3637\text{ L.mmHg }mol^{-1}K^{-1}

T = Temperature of hydrogen gas = 21^oC=[21+273]K=294K

Putting values in above equation, we get:

733.35mmHg\times V=0.0851mol\times 62.3637\text{ L.mmHg }mol^{-1}K^{-1}\times 294K\\\\V=\frac{0.0851\times 62.3637\times 294}{733.35}=2.13L

Hence, the volume of hydrogen gas collected over water is 2.13 L

5 0
3 years ago
What is the molecular formula of a compound containing 89% cesium (Cs) and 11% oxygen (O) with a molar mass = 298 g/mol?
Maurinko [17]
M(Cs)=133 g/mol
M(O)=16 g/mol
M(CsxOy)=298 g/mol
w(Cs)=0.89
w(O)=0.11

CsxOy

x=M(CsxOy)w(Cs)/M(Cs)
x=298*0.89/133=2

y=M(CsxOy)w(O)/M(O)
y=298*0.11/16=2

Cs₂O₂  cesium peroxide
6 0
3 years ago
Read 2 more answers
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