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Vsevolod [243]
3 years ago
9

How many joules are in 10,000 Electron Volts

Physics
2 answers:
tatiyna3 years ago
7 0
1.602177e-15 joules are present in 10,000 Electron Volts :)
Semenov [28]3 years ago
5 0
1.602177e-15 joules are in 10,000 electron volts

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An organ pipe is open at both ends. It is producing sound
ozzi

To solve this problem we will apply the concepts related to the wavelength of its third harmonic.

It describes that the wavelength is equivalent to

\lambda = \frac{2}{3}L

Here,

\lambda = Wavelength

The wavelength is in turn described as a function that depends on the change of the speed as a function of the frequency, that is to say

\lambda = \frac{v}{f}

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\lambda = \frac{343}{262}

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L = 1.963m

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A car goes from rest to a velocity of 108 km/h north in 10s what is the car's acceleration in m/s2
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initial velocity of the car given as

v_i = 0

final velocity is given as

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v_f = 108 * 0.277 = 30 m/s

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A beach ball with a volume of 5,000 cm3 is pushed underwater. What is the magnitude of the buoyant force pushing upwards? The de
Kobotan [32]
<h2>Hello!</h2>

The answer is:

The buoyant force is equal to 49N.

<h2>Why?</h2>

The buoyant force is the force that pushes upwards and object when it's submerged in water, this force is always trying to move the object to the surface of the liquid or water.  We must consider that the volume of water or liquid displaced is equal to the volume of the submerged object.

We can calculate the buoyant force using the following formula:

F_{B}=Density*VolumeDisplaced*GravityAcceleration

Where,

Density is the density of the water or liquid.

Volume displaced is equal to the volume of the submerged object.

Gravity acceleration is the acceleration due to gravity.

So, from the statement we know that:

VolumeDisplaced=BeachBallVolume=5000cm^{3}\\\\Density=1\frac{gram}{cm^{3} }=\frac{0.001kg}{cm^{3} }\\\\g=9.8\frac{m}{s^{2} }

Now, substituting and calculating we have:

F_{B}=Density*VolumeDisplaced*GravityAcceleration

F_{B}=0.001\frac{kg}{cm^{3}*} *5000cm^{3}*9.8\frac{m}{s^{2} }

F_{B}=0.001\frac{kg}{cm^{3}*} *5000cm^{3}*9.8\frac{m}{s^{2} }

F_{B}=49\frac{Kg.m}{s^{2}}=49N

Hence, we have that the correct answer is:

The buoyant force is equal to 49N.

Have a nice day!

7 0
4 years ago
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