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3 years ago

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An object is placed on the axis of a converging mirror of focal length 200mm. The image produced is inverterd and has a magnific

ation of 1.5.By calculation or by scale drawing on a graph paper determine the position of the object

1 answer:

sp2606 [1]3 years ago

6 0

Answer:1.7 is the answer

Explanation:im smart

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Help with this please.

gregori [183]

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3 years ago

If the height of the ramp was 1.2 m above the floor, how long would it take for the marble to hit the ground after it left the r

Evgesh-ka [11]

It would take at less 10 minte i guess this the right awnser

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3 years ago

45. What is the wovelength of a 30. Hertz periodic

Leviafan [203]

The wavelength is 2m.

Hence, Option c) 2m is the correct answer

Given that;

Frequency; $f = 30Hz$

Speed; $v = 60m/s$

Wavelength; $\lambda =\ ?$

using the expression for the relations between wavelength, frequency and speed of wave:

$\lambda = \frac{v}{f}$

Where $\lambda$ is wavelength, f is frequency and v is speed.

We substitute our given values into the equation

$\lambda = \frac{60m/s}{30Hz}\\\\\lambda = \frac{60m/s}{30s^{-1}}\\\\\lambda = 2m$

The wavelength is 2m.

Hence, Option c) 2m is the correct answer.

To learn more about wavelength, click here: brainly.com/question/1347107

4 0

2 years ago

What affects sounds at their source? MENTION DOPPLER EFFECT AND VIBRATIONS

wel

Answer:

Doppler effect, the apparent difference between the frequency at which sound or light waves leave a source and that at which they reach an observer, caused by relative motion of the observer and the wave source. This phenomenon is used in astronomical measurements, in Mössbauer effect studies, and in radar and modern navigation.

Explanation:

6 0

3 years ago

A cannon fires a 0.2 kg shell with initial velocity vi = 9.2 m/s in the direction θ = 46 ◦ above the horizontal. The shell’s tra

Sedbober [7]

Answer:

∆h = 0.071 m

Explanation:

I rename angle (θ) = angle(α)

First we are going to write two important equations to solve this problem :

Vy(t) and y(t)

We start by decomposing the speed in the direction ''y''

$sin(\alpha) = \frac{Vyi}{Vi}$

$Vyi = Vi.sin(\alpha ) = 9.2 \frac{m}{s} .sin(46) = 6.62 \frac{m}{s}$

Vy in this problem will follow this equation =

$Vy(t) = Vyi -g.t$

where g is the gravity acceleration

$Vy(t) = Vyi - g.t= 6.62 \frac{m}{s} - (9.8\frac{m}{s^{2} }) .t$

This is equation (1)

For Y(t) :

$Y(t)=Yi+Vyi.t-\frac{g.t^{2} }{2}$

We suppose yi = 0

$Y(t) = Yi +Vyi.t-\frac{g.t^{2} }{2} = 6.62 \frac{m}{s} .t- 4.9\frac{m}{s^{2} } .t^{2}$

This is equation (2)

We need the time in which Vy = 0 m/s so we use (1)

$Vy (t) = 0\\0=6.62 \frac{m}{s} - 9.8 \frac{m}{s^{2} } .t\\t= 0.675 s$

So in t = 0.675 s → Vy = 0. Now we calculate the y in which this happen using (2)

$Y(0.675s) = 6.62\frac{m}{s}.(0.675s)-4.9 \frac{m}{s^{2} } .(0.675s)^{2} \\Y(0.675s) =2.236 m$

2.236 m is the maximum height from the shell (in which Vy=0 m/s)

Let's calculate now the height for t = 0.555 s

$Y(0.555s)= 6.62 \frac{m}{s} .(0.555s)-4.9\frac{m}{s^{2} } .(0.555s)^{2} \\Y(0.555s) = 2.165m$

The height asked is

∆h = 2.236 m - 2.165 m = 0.071 m

6 0

3 years ago