Question

4. Ammonium nitrate (NH4NO3) fertilizer decomposes explosively into gaseous nitrogen, oxygen, and water, resulting in huge thermal energy produces hot and damaging gases. How much nitrogen can we introduce in our garden when 800 grams of ammonium nitrate (NH4NO3)

Answer 1

Answer:

280 g

Explanation:

Let's consider the decomposition of ammonium nitrate.

NH₄NO₃(s) ⇒ N₂(g) + 0.5 O₂(g) + 2 H₂O(g)

We can establish the following relations:

• The molar mass of NH₄NO₃ is 80.04 g/mol.
• The molar ratio of NH₄NO₃ to N₂ is 1:1.
• The molar mass of N₂ is 28.01 g/mol.

The mass of N₂ produced when 800 g of NH₄NO₃ react is:

$800gNH_{4}NO_{3}.\frac{1molNH_{4}NO_{3}}{80.04gNH_{4}NO_{3}} .\frac{1molN_{2}}{1molNH_{4}NO_{3}} .\frac{28.01gN_{2}}{1molN_{2}} =280gN_{2}$