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Arte-miy333 [17]
3 years ago
13

A right triangle with base labeled Vector J = 6, the height labeled Vector K = unknown and the hypotenuse labeled Vector L = 10

meters. What is the magnitude of vector K
Physics
1 answer:
svet-max [94.6K]3 years ago
5 0

Answer:

K = 8

Explanation:

The magnitude of k can be found using Pythagoras theorem.

Given hypotenuse L = 10

J = 6

K = ?

L^2 = J^2 + k^2

Therefore

10^2 = 6^2 + k^2

10 x 10 = 6 x 6 c k^2

100 = 36 + k^2

Subtract 36 from both sides

100 - 36 = 36 - 36 + k^2

64 = k^2

K^2 = 64

K = squared root of 64

K = 8

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Water flows through a horizontal pipe of varying cross-section. In the first section, the cross-sectional area is 10 cm2 and flo
Stels [109]

Answer:

(a) the flow speed of the second section is 11 m/s

(b) the pressure of the second section is 6.33 x 10⁴ Pa

Explanation:

Given;

flow rate in the first section, Q₁ = 2750 cm³/sec

area of the first cross section, A₁ = 10 cm²

pressure in the first cross section, P₁ = 1.2 x 10⁵ Pa

area of the second section, A₂ = 2.5 cm²

(a) the flow speed of the second section (V₂)

Apply continuity equation;

Q₁ = Q₂

Q₁ = A₂V₂

V₂ = Q₁ / A₂

V₂ = (2750) / (2.5)

V₂ = 1100 cm/s = 11 m/s

(b) the pressure of the second section (P₂)

Apply Bernoulli's equation;

P₁ + ¹/₂ρV₁² = P₂ + ¹/₂ρV₂²

where;

ρ is density of water = 1000 kg/m³

V₁ is the speed of water in the first section;

Q₁ = A₁V₁

V₁ = Q₁ / A₁

V₁ = (2750) / (10)

V₁ = 275 cm/s = 2.75 m/s

P₂ = P₁ + ¹/₂ρV₁² - ¹/₂ρV₂²

P₂ = P₁ + ¹/₂ρ(V₁² - V₂²)

P₂ = 1.2 x 10⁵ Pa + ¹/₂ x 1000 (2.75² - 11²)

P₂ = 1.2 x 10⁵ Pa + 500(-113.438)

P₂ = 1.2 x 10⁵ Pa - 0.567  x 10⁵ Pa

P₂ = 0.633 x 10⁵ Pa

P₂ = 6.33 x 10⁴ Pa

8 0
3 years ago
The nucleus of an atom is composed of unchanged particles as well as of the following
Ivan
I suppose that you wanted write "uncharged". The particles without electrical charge present in the nucleus are called neutrons.
7 0
3 years ago
In a laboratory, it is often convenient to make measurements in centimeters and grams, but SI units are needed for calculations.
zheka24 [161]

Answer:

(a) 0.92 cm= 0.092 m.

(b) 141.64 g=0.14164 kg.

(c) 15. 8 cm³=0.0000158 m³

(d) 63.6 g/cm³= 63600 kg/m³

Explanation:

The International System of Units, abbreviated S.I., also called the International System of Measurements is a system of measurements in which its units are based on fundamental physical phenomena. The units of the S.I. They are the international reference for the indications of all measuring instruments.

The International System of Units (SI) arose from the need to unify and give coherence to a great variety of unit subsystems.

The International System of Units consists of seven basic units, also called fundamental units, which define the corresponding fundamental physical quantities and which allow any physical quantity to be expressed in terms or as a combination of them. The fundamental physical quantities are complemented by two more physical quantities, called supplementary ones.

By combining the basic units, the other units are obtained, called units derived from the International System, and which allow defining any physical quantity.

(a)  The SI unit of length is the meter. Being 1 cm = 0.01 m, then <u><em>0.92 cm= 0.092 m.</em></u>

(b)  The SI unit of mass is kg. Being 1 g = 0.001 kg, then <u><em>141.64 g=0.14164 kg.</em></u>

(c) Being 1 cm³ = 0.000001 m³, then <u><em>15. 8 cm³=0.0000158 m³</em></u>

(d) Being 1 g/cm³= 1000 kg/m³, then <u><em>63.6 g/cm³= 63600 kg/m³</em></u>

3 0
3 years ago
Can force be two-dimensional?
nata0808 [166]

Answer:

Yes

Explanation:

Just as motion in two dimensions introduced vectors, forces in two dimensions also involve more involved issues. 

3 0
3 years ago
Imagine that you pushed a box, applying a force of 60 newtons, over a distance of 4 meters. How much would you have done?
grin007 [14]
You would have done 240 joules of work on the box.

Work = (force)  x  (distance)

         =  (60 newtons)  x  (4 meters)

         =         240 joules  . 
5 0
3 years ago
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