Answer:
(a) x = 0.25 m
(b) v = 1.46 m/s
(c) v = 2.4 m/s
Explanation:
mass (m) = 10.3 kg
force from thrust (F) = 240 N
spring constant (k) = 400 N/m
stretch distance from thrust (y) = 30 cm = 0.3 m
acceleration due to gravity (g) = 9.8 m/s^{2}
(A) from mg = kx
compression (x) = mg/ k
x = 
x = 0.25 m
(B) from the conservation of forces
(Fy) + (0.5k
) = (0.5k
) + mgh + (0.5m
)
v =
) - (0.5k
) - mgh }{0.5m}[/tex]}[/tex]
v =
) - (0.5 x 400 x
) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 1.46 m/s
(C) if the rocket weren't attached to the spring, the conservation of energy equation becomes
(Fy) + (0.5k
) = mgh + (0.5m
)
v =
) - mgh }{0.5m}[/tex]}[/tex]
v =
) - (10.3 x 9.8 x (0.25 + 0.3)) }{0.5 x 10.3}[/tex]}[/tex]
v = 2.4 m/s