1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alona [7]
3 years ago
5

Determine the acceleration of a boat with a final speed of 120 m/s after 30 seconds.

Physics
2 answers:
laila [671]3 years ago
8 0

Answer:

ehehehshehehehhehesh

Explanation:

ehehehehheheheeheh

Anuta_ua [19.1K]3 years ago
6 0
V=u+at
120=0+a*30
120=30a
a=120/30
a=4 m/s²
You might be interested in
Metals such as aluminum can be formed into thin sheets because they are
Korvikt [17]

Answer:

They are malleable.

Explanation:

Malleability is the property of metals that causes them to be able to be formed into thin sheets without breaking.

All metals are malleable.

The reason why metals are malleable is because the atoms in the metals have a stable structure and hence, when beaten, the atoms can move freely among each other and maintain their structure.

8 0
3 years ago
Read 2 more answers
how does distance change when the amount of effort force is increasesd while the amount of work done remains the same?
nlexa [21]
Could you supply u with some answer choices please?
8 0
4 years ago
Failure to accomplish Erikson’s psychosocial task of late adulthood leads to despair.
Y_Kistochka [10]
False is the answer
6 0
4 years ago
Read 2 more answers
A person who is good at caring for others might enjoy a career as a
julia-pushkina [17]
He or she would enjoying doing a job as a caretaker
5 0
3 years ago
A 37 kg object has an applied force of 85N [R] acting on it. The coefficient of
Sliva [168]

Answer:

Explanation:

This is quite tricky! You need to do 2 different equations to solve all the parts of this problem. First is finding the acceleration in one dimension, which has an equation of

F - f = ma

where F is the applied Friction,

f is the frictional force acting against F,

m is the mass of the object, and

a is the acceleration of the object (NOT the velocity!)

This is Newton's Second Law expanded on a bit. The sum of the forces working on an object is equal to the object's mass times its acceleration. We have F, but we need f which is found in the equation

f = μF_n which is the coefficient of kinetic friction times the weight of the object. Weight is found in the equation

w = mg where m is mass and g is the pull of gravity. Let's start there and work backwards:

w = 37(9.8) to 2 sig figs so

w = 360N. Now fill that in to find f:

f = (.17)(360) to 2 sig figs so

f = 61. Now for the final answer in the original equation way back up at the top:

85 - 61 = 37a and do the subtraction on the left side first:

24 = 37a and then we divide to 2 sig figs to get

a = .65 m/s/s

Since we are moving in a straight line (as opposed to on an angle) the displacement is found in

d = rt which simply says that the distance an object moves is equal to its rate times the time. Therefore,

d = 2.2(3.4) to 2 sig figs so

d = 7.5 m

6 0
3 years ago
Other questions:
  • A block attached at the end of a spring undergoes simple harmonic motion with frequency of oscillation ω.
    10·2 answers
  • If the net force on an object is zero, what is the acceleration?
    12·1 answer
  • Can I PLEASE get some help? I REALLY need it!
    7·1 answer
  • why should it take significantly more energy to move a beam of alpha particles than a beam of beta minus particles
    9·1 answer
  • Chemical energy is energy that
    14·1 answer
  • What force is needed to accelerate an object 5 m/s if the object has a mass of 10kg?
    5·1 answer
  • A 5.85-mm-high firefly sits on the axis of, and 13.7 cm in front of, the thin lens A, whose focal length is 5.01 cm. Behind lens
    8·1 answer
  • Question 1<br> 2 pts<br> Explain what causes a solution to be a strong acid.
    5·1 answer
  • Can y’all answer these questions pls?
    8·2 answers
  • (50 Points)
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!