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aleksandrvk [35]

3 years ago

8

Find an expression for the frequency of oscillations perpendicular to the rubber bands. assume the amplitude is sufficiently sma

ll that the magnitude of the tension in the rubber bands is essentially unchanged as the mass oscillates.

1 answer:

bearhunter [10]3 years ago

7 0

Check the attached file for the answer.

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3. When you graph the motion of an object, you put ____ on the horizontal axis and ____ on the axis. a. speed, time b. dis

Papessa [141]

The answer is B. distance , Time

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3 years ago

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A stationary charge is located between the poles of a horseshoe magnet. Is a magnetic force excerted of the charge? why?

vredina [299]

A stationary charge is located between the poles of a horseshoe magnet. The magnetic force exerted by the charge is zero.

<h3>What is charge?</h3>

Charge is the physical property of matter which cause a particle to attract or repel when placed in its field.

A stationary charged particle does not interact with a static magnetic field. A charge placed in a magnetic field experiences a magnetic force. There will be no magnetic force acting on a stationary charge. The charge must be moving in order to have magnetic force on it.

Thus, the magnetic force exerted by the charge is zero.

Learn more about charge.

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7 0

2 years ago

The amount of heat required to melt lead at it melting temperature is 23.0 kJ/kg. The amount of heat required to melt mercury at

svet-max [94.6K]

The addition of 24 kJ of energy will allow all of the mercury and lead to change from solid to liquid. The temperature of each substance will also increase.

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3 years ago

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Observe yourself breathing and count the number of times you inhale per second. During each breath you probably inhale 0.66 L of

Pavel [41]

To solve this exercise it is necessary to apply the concepts related to Robert Boyle's law where:

$PV=nRT$

Where,

P = Pressure

V = Volume

T = Temperature

n = amount of substance

R = Ideal gas constant

We start by calculating the volume of inhaled O_2 for it:

$V = 21\% * 0.66L$

$V = 0.1386L$

Our values are given as

P = 1atm

T=293K $R = 0.083145kJ*mol^{-1}K^{-1}$

Using the equation to find n, we have:

$PV=nRT$

$n = \frac{PV}{RT}$

$n = \frac{(1)(0.1386)}{(0.0821)(293)}$

$n = 5.761*10^{-3}mol$

Number of molecules would be found through Avogadro number, then

$\#Molecules = 5.761*10^{-3}*6.022*10^{23}$

$\#Molecules = 3.469*10^{21} molecules$

7 0

3 years ago

All the planets orbit the Sun

aivan3 [116]

Answer:

Yes, they do

Explanation:

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3 years ago

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