<u>Explanation</u>:
As per given question,
R is 0.895 m
The force between two objects is
Where,
F is the force of attraction between two objects in Newton’s (N)
R is the separation in meters (m) between the objects
Substitute the given values in the above formula,
Answer:
a) Therefore 2.6km is greater than 2.57km.
Statement A is greater than statement B.
b) Therefore 5.7km is equal to 5.7km
Statement A is equal to statement B
Explanation:
a) Statement A : 2.567km to two significant figures.
2.567km 2. S.F = 2.6km
Statement B : 2.567km to three significant figures.
2.567km 3 S.F = 2.57km
Therefore 2.6km is greater than 2.57km.
Statement A is greater than statement B.
b) statement A: (2.567 km + 3.146km) to 2 S.F
(2.567km + 3.146km) = 5.713km to 2 S.F = 5.7km
Statement B : (2.567 km, to two significant figures) + (3.146 km, to two significant figures).
2.567km to 2 S.F = 2.6km
3.146km to 2 S.F = 3.1km
2.6km + 3.1km = 5.7km
Therefore 5.7km is equal to 5.7km
Statement A is equal to statement B
Answer:
P=1.53 i +1.92 j kg.m/s
P=2.45 kg.m/s
α = 51.34
Explanation:
Given that
m=123 g = 0.123 Kg
U= 25 m/s
θ=30°
t= 0.6 s
This is the case of projectile motion
So the horizontal component of velocity U = u cosθ
u = 25 cosθ
u = 25 cos 30°
u=21.65 m/s
The vertical component of velocity U = U sinθ
Vo= U sinθ
Vo= 25 sin 30°
Vo = 12.5 m/s
We know that horizontal component of velocity of ball will remain same.So the horizontal component of momentum
Px= m u
Px= 0.143 x 12.5 kg.m/s
Px=1.53 kg.m/s
The vertical component of ball after 0.6 s
V= Vo- g t
V= 21.65 - 10 x 0.6 m/s
V= 15.65 m/s
Py= m V
Py= 0.123 x 15.65 kg.m/s
Py=1.92 kg.m/s
P=1.53 i +1.92 j kg.m/s
Magnitude P
P=2.45 kg.m/s
Direction
α = 51.34° (measured from x direction)
Answer:
41.4* 10^4 N.m^2/C
Explanation:
given:
E= 4.6 * 10^4 N/C
electric field is 4.6 * 10^4 N/C and square sheet is perpendicular to electric field so, area of vector is parallel to electric field
then electric flux = ∫ E*n dA
= ∫ 4.6 * 10^4 * 3*3
= 41.4* 10^4 N.m^2/C