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3 years ago

Use the half-reactions of the reaction Au(OH)3 + HI -> Au +I2 +H2O to answer the questions

Chemistry

2 answers:

kirill115 [55]3 years ago

4 0

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below
Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - carbon monoxide
To enter an electron into a chemical equation use {-} or e
To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.
Example: Fe{3+} + I{-} = Fe{2+} + I2
Substitute immutable groups in chemical compounds to avoid ambiguity.
For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,
but PhC2H5 + O2 = PhOH + CO2 + H2O will
Compound states [like (s) (aq) or (g)] are not required.
If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.

kramer3 years ago

3 0

Answer: gold gains 3

Iodine loses 1

The total is 6

Explanation:

You might be interested in

What are the reactants in a neutralization reaction?

castortr0y [4]

answer an element and a compound

8 0

3 years ago

Calculate the change in energy when 75.0 grams of water drops from 31.0C to 21.6.

zysi [14]

Answer: Step 1: Calculate qsur (the surrounding is

usually the water)

qsur = ? J

m = 75.0 g water

c = 4.184 J/g

ΔT = (Tfinal- Tinitial)= (21.6 – 31.0) = -9.4 oC

qsur = m · c · (ΔT)

qsur = (75.0g) (4.184 J/g

oC) (-9.4 oC)

qsur = - 2949.72 J

First, using the information we know that we

must solve for qsur, which is the water. We know

the mass for water, 75.0g, the specific heat of

the water, 4.184 j/g

c, and the change in

temperature, 21.6-31.0 = -9.4 oC. Plugging it

into the equation, we solve for qsur.

Step 2: Calculate qsys qsys = - (qsur)

qsys = - (- 2949.72 J)

qsys = + 2949.72

In this case, the qsur is negative, which means

that the water lost energy. Where did it go? It

went to the system. Thus, the energy of the

system is negative, opposite, the energy of the

surrounding.

Step 3: Calculate moles of the substance

that is the system

Given: 12.8 g KCl

Mol system = (g system given)

(molar mass of system)

Mol system = (12.8 g KCl)

(39.10g + 35.45g)

Mol system = 12.8 g KCl

74.55 g

Mol system = 0.172

Here, we solve for the mol in the system by

using the molar mass of the material in the

system.

Step 4: Calculate ΔH ΔH = q sys .

Mol system

ΔH= + 2949.72 J

0.172 mol

ΔH= +17179.81 J/mol or +1.72 x 104

J/mol

i hope this helps

5 0

3 years ago

Read 2 more answers

How do you calculate mass using density and volume?

skad [1K]

Example:

Mass = ?

Density = 25 g/mL

Volume = 5 mL

therefore:

d = m / V

25 = m / 5

m = 25 x 5

m = 125 g

hope this helps!

7 0

3 years ago

10. When a piece of steel wool is burned it gains mass. Which explanation is consistent with the law of conservation of mass?

frez [133]

Answer:

Oh come on. Look at all - then look at A.

Explanation:

4 0

3 years ago

Which is the balanced single displacement reaction between Aluminum (Al3+) and Copper Sulfate (Cu2+(SO4)2-)

Aliun [14]

Answer:

The balanced single displacement reaction between aluminum and copper sulphate is as follows.

$2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)$

Explanation:

The given ions are as follows.

$Al^{3+}$ - Aluminium ion and copper sulfate ion.

Single displacement reaction occurs one element replaces another element.

Hence, the balanced chemical reaction is as follows.

$2Al(s)+3CuSO_{4}(aq)\rightarrow Al_{2}(SO_{4})_{3}(aq)+3Cu(s)$

Oxidation half reaction:

$Al\rightarrow Al^{3+}+3e^{-}$

Aluminium loses three electrons.

Reduction half reaction:

$Cu^{2+}+2e^{-}\rightarrow Cu(s)$

Copper gain three electrons.

4 0

3 years ago