All categories

3 years ago

Use the half-reactions of the reaction Au(OH)3 + HI -> Au +I2 +H2O to answer the questions

Chemistry

2 answers:

kirill115 [55]3 years ago

4 0

Enter an equation of a chemical reaction and click 'Balance'. The answer will appear below
Always use the upper case for the first character in the element name and the lower case for the second character. Examples: Fe, Au, Co, Br, C, O, N, F. Compare: Co - cobalt and CO - carbon monoxide
To enter an electron into a chemical equation use {-} or e
To enter an ion specify charge after the compound in curly brackets: {+3} or {3+} or {3}.
Example: Fe{3+} + I{-} = Fe{2+} + I2
Substitute immutable groups in chemical compounds to avoid ambiguity.
For instance equation C6H5C2H5 + O2 = C6H5OH + CO2 + H2O will not be balanced,
but PhC2H5 + O2 = PhOH + CO2 + H2O will
Compound states [like (s) (aq) or (g)] are not required.
If you do not know what products are enter reagents only and click 'Balance'. In many cases a complete equation will be suggested.

kramer3 years ago

3 0

Answer: gold gains 3

Iodine loses 1

The total is 6

Explanation:

You might be interested in

A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 30 m during the next 40 s.

Doss [256]

Answer:

$\boxed{\text{0.76m/s}}$

Explanation:

$\text{Average speed} = \dfrac{\text{total distance}}{\text{total time}}$

Total distance = 2 m + 30 m = 32 m

Total time = 2 s + 40 s = 42 s

$\text{Average speed} = \dfrac{\text{32 m}}{\text{42 s}} = \textbf{0.76 m/s}\\\text{The average speed of the object is $\boxed{\textbf{0.76m/s}}$}$

5 0

4 years ago

Compare a sodium ion and neutral sodium atom in size. what causes the size difference

n200080 [17]

A cation is smaller than its parent atom.
Therefore, here a sodium ion is smaller than the neutral sodium atom.

Reason: Since the sodium atom loses an electron to form an electropositive ion(cation), its nuclear charge increases(the number of protons exceeds the number of electrons) and the orbital electrons are pulled with a greater energy.
Thus,the sodium ion shrinks in size.

4 0

3 years ago

A cylinder is filled with 10.0L of gas and a piston is put into it. The initial pressure of the gas is measured to be 96.0kPa. T

Norma-Jean [14]

Answer:

The final pressure of the gas is:- 21.3 kPa

Explanation:

Using Boyle's law

${P_1}\times {V_1}={P_2}\times {V_2}$

Given ,

V₁ = 10.0 L

V₂ = 45.0 L

P₁ = 96.0 kPa

P₂ = ?

Using above equation as:

${P_1}\times {V_1}={P_2}\times {V_2}$

${96.0\ kPa}\times {10.0\ L}={P_2}\times {45.0\ L}$

${P_2}=\frac {{96.0}\times {10.0}}{45.0}\ kPa$

${P_2}=21.3\ kPa$

The final pressure of the gas is:- 21.3 kPa

3 0

3 years ago

You are given two aqueous solutions with different ionic solutes (Solution A and Solution B). What if you are told that Solution

klio [65]

Answer:

Yes, it is possible. Let us consider an example of two solutions, that is, solution A having 20 percent mass RbCl (rubidium chloride) and solution B is having 15 percent by mass NaCl or sodium chloride.

It is found that solution A is having more concentration in comparison to solution B in terms of mass percent. The formula for mass percent is,

% by mass = mass of solute/mass of solution * 100

Now the formula for molality is,

Molality = weight of solute/molecular weight of solute * 1000/ weight of solvent in grams

Now molality of solution A is,

m = 20/121 * 1000/80 (molecular weight of RbCl is 121 grams per mole)

m = 2.07

Now the molality of solution B is,

m = 15/58.5 * 1000/85

m = 3.02

Therefore, in terms of molality, the solution B is having greater concentration (3.02) in comparison to solution A (2.07).

5 0

3 years ago

Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting e

seropon [69]

Answer:

C2H3Br + O2 → CO2 + H2O + HBr

Explanation:

The term balancing of chemical reaction equation has a unique meaning in chemistry. What it actually means is to ensure that the number of atoms of each element on the left hand side of reaction equation becomes equal to the number of atoms of the same element on the right hand side of the reaction equation.

When we look at the equation; C2H3Br + O2 → CO2 + H2O + HBr, the number of atoms of each element on the left and right hand sides of the given equation are not the same hence the equation is unbalanced.

If we look at the equation; 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr, the number of atoms of each element on both sides of the reaction equation are now equal, thus the later equation is the balanced version of the former.

6 0

3 years ago