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Lostsunrise [7]
3 years ago
6

What zone has warm water and a lot of sunlight; ocean floor starts to slope downward?

Physics
2 answers:
gregori [183]3 years ago
8 0
The oceanic zone has warm water and a lot of sunlight, ocean floor starts to slope downwards.
igor_vitrenko [27]3 years ago
4 0
<span>C. Oceanic zone hope this helpes

</span>
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What's the difference and similarity between O2 and 2 O ?
nasty-shy [4]
O2 refers to two oxygen atoms bonded together, while 2 O refers to two oxygen atoms that are not bonded to each other. They both have two oxygen atoms, but in O2, the oxygen atoms are bonded, while in 2O, the atoms are not.
4 0
3 years ago
A 300-n force acts on a 25-kg object. the acceleration of the object is?
Over [174]
To solve the answer use the equation: a = fnet / m

a = 300 N / 25 kg

300 N / 25 kg = 12m/s

The acceleration of the object is 12m/s

8 0
2 years ago
Read 2 more answers
3. Maverick and Goose are flying a training mission in their F-14. They are
Elanso [62]

Answer:

A. The bomb will take <em>17.5 seconds </em>to hit the ground

B. The bomb will land <em>12040 meters </em>on the ground ahead from where they released it

Explanation:

Maverick and Goose are flying at an initial height of y_0=1500m, and their speed is v=688 m/s

When they release the bomb, it will initially have the same height and speed as the plane. Then it will describe a free fall horizontal movement

The equation for the height y with respect to ground in a horizontal movement (no friction) is

y=y_0 - \frac{gt^2}{2}    [1]

With g equal to the acceleration of gravity of our planet and t the time measured with respect to the moment the bomb was released

The height will be zero when the bomb lands on ground, so if we set y=0 we can find the flight time

The range (horizontal displacement) of the bomb x is

x = v.t     [2]

Since the bomb won't have any friction, its horizontal component of the speed won't change. We need to find t from the equation [1] and replace it in equation [2]:

Setting y=0 and isolating t we get

t=\sqrt{\frac{2y_0}{g}}

Since we have y_0=1500m

t=\sqrt{\frac{2(1500)}{9.8}}

t=17.5 sec

Replacing in [2]

x = 688\ m/sec \ (17.5sec)

x = 12040\ m

A. The bomb will take 17.5 seconds to hit the ground

B. The bomb will land 12040 meters on the ground ahead from where they released it

6 0
2 years ago
A wire that is 0.86 meters long is moved perpendicularly through a constant magnetic field of strength 0.035 newtons/amp·meter a
GaryK [48]
The emf induced = B*l*v where B is the flux density, l the length of the conductor and v the velocity of the conductor. In the given case B = 0.035 N/amp.meter, l = 0.86 and v = 6 m/sec
emf = 0.035*0.86*6 = 0.1806 v ≈ 0.18 v
choice: D
6 0
3 years ago
All of the following are factors affecting flow rate except what?
faust18 [17]

Answer:

c. Vessel side holes

Explanation:

  • The "Poiseuille formula" which is given by \\\begin{aligned} \small Q& =  \small \frac{\pi r^4}{8 \eta}.\frac{\Delta P}{\Delta L}\\\end{aligned} describes the volumetric flow rate (\small Q) through tubular sections.
  • Here, \Delta P,\,\, \Delta L,\,\, r,\,\, \eta represent the injection pressure difference, the length of the section, the radius of the section and the viscosity index of the fluid that flows through the section respectively.
  • With this, one can confirm that all the factors except the vessel side holes affect the flow rate.
  • Side holes, however, are a factor that could give a measure of how much volume would flow to a particular location. In such a situation the flow rate remains unchanged and one location would receive a lower volume (not the whole) as some volume would spill out at the side holes.

#SPJ4

5 0
2 years ago
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