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RoseWind [281]
3 years ago
12

Describe 2 physical and 2 chemical changes involved in cooking Please answer quick!!!

Chemistry
1 answer:
pshichka [43]3 years ago
7 0

Answer: theres alot let me explain...

Explanation:

Protein denaturation is what makes eggs solidify, collagen break down and convert to gelatin in slow-cooked meat, fish and chicken become more opaque, and all meats firm up and change color. This is primarily achieved by applying heat, but can also occur in the presence of acidic and basic ingredients.

The Maillard reaction is the primary effect taking place in “browning”, and produces more flavor compounds, resulting in more complex flavors in food that we generally find enjoyable. It involves reaction between amino acids (proteins) and a certain class of sugars called reducing sugars — mostly the monosaccharides, such as glucose and fructose.

Caramelization is a secondary browning effect that occurs in foods with sugar content, even though all browning is often referred to as “caramelizing”. It mostly takes place at higher temperatures than Maillard reaction (with the notable exception of fructose).

Pyrolysis, or thermal decomposition (chemical breakdown) begins at higher temperatures. While caramelization is technically in this category, the main effect of this reaction is carbonization. This is what we generally mean when we talk about “burning” food, even though no combustion has taken place. It’s also what happens when we cause oil to smoke and darken. In small, controlled amounts, this can still provide desirable flavors, such as char on the outside of meat and contributing to “wok hei” in stir frying — the latter of which does involve some combustion.

Acid-base reactions produce carbon dioxide, which creates the rise in quick breads such as biscuits. These often occur at room temperature, but some also don’t occur until higher temperatures — which is how “double-acting” baking powder works.

Gluten formation occurs when you mix flour and water, resulting in stretchy doughs and fluffy baked goods. This occurs easily at room temperature.

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1. A 9.941 gram sample of an organic compound containing C, H and O is analyzed by combustion analysis and 14.57 grams of CO2 an
salantis [7]

Answer:

1) empirical formula = CH2O ; the molecular formula = C2H402

2) empirical formule = C3H404 = Molecular formula

Explanation:

CxHyOz  → CO2 + H2O

⇒ So for CO2 we can say that for each 1 C-atom (12g) there are 2 O-atoms (32g).

This means the ratio is 12g C/ 32g O

CO2 has a molar mass of 44 g/mole

in 14.57 grams of CO2 there is: (12g Carbon / 44g CO2) * 14.57 g CO2 = 3.9736 g Carbon

⇒For H2O we can do the same:

The ratio of each element in H2O is: 2 H-atoms/ 1 O-atom  This is 2g H/ 16g O

In 5.966 g of water there are: [2 g H / 18 g H2O] * 5.966 g H2O = 0.6629 g H

⇒The original sample had 9.941 g of Sample - 3.9736 g of C - 0.6629 g of H =  5.3045 g of O

2) Calculate number of moles

C: 3.9736 g / 12.0 g/mol = 0.3311 mol

H: 0.6629 g / 1.0 g/mol = 0.6629 mol

O: 5.3045g / 16.0 g/mol =  0.3315 mol

3) Now we should divide each number of mole by the smallest number (0.3311) to find the proportion of the elements

C: 0.3311/ 0.3311= 1

H: 0.6629 / 0.3311 = 2

O: 0.3315/ 0.3311  = 1

This gives us the empirical formula of CH2O

4) Calculate the mass of the empirical formula

Molar mass of Carbon = 12g /mole

Molar mass of Hydrogen = 1g /mole

Molar mass of Oxygen = 16g /mole

mass of the empirical formule = 12 + 2*1 + 16 = 30g

5) Calculate the molecular formula

mass of molecular formule / mass of empirical formula = n

We have to multiply the empirical formula by n to get the molecular formula.

60 / 30 = 2 = n

If we multiply CH2O by 2 we'll get: C2H4O2

If we control this by calculating the molar mass:

2*12 + 4*1.01 + 2*16 = 60.04 g/mole

Then, the molecular formula is C2H4O2

CxHyOz  → CO2 + H2O

⇒ So for CO2 we can say that for each 1 C-atom (12g) there are 2 O-atoms (32g).

This means the ratio is 12g C/ 32g O

CO2 has a molar mass of 44 g/mole

in 17.97 grams of CO2 there is: (12g Carbon / 44g CO2) * 17.97 g CO2 = 4.90 g Carbon

⇒For H2O we can do the same:

The ratio of each element in H2O is: 2 H-atoms/ 1 O-atom  This is 2g H/ 16g O

In 4.905 g of water there are: [2 g H / 18 g H2O] * 4.905 g H2O = 0.545 g H

⇒The original sample had 14.16 g of Sample - 4.90 g of C - 0.545 g of H =  8.715g of O

2) Calculate number of moles

C: 4.90 g / 12.0 g/mol = 0.4083 mol

H: 0.545 g / 1.0 g/mol = 0.545 mol

O: 8.715g / 16.0 g/mol =  0.5447 mol

3) Now we should divide each number of mole by the smallest number (0.4083) to find the proportion of the elements

C: 0.4083/ 0.4083= 1

H: 0.545 / 0.4083 =1.33

O: 0.5447/ 0.4083  = 1.33

We should multiply everything by 3

This gives us the empirical formula of C3H4O4

4) Calculate the mass of the empirical formula

Molar mass of Carbon = 12g /mole

Molar mass of Hydrogen = 1g /mole

Molar mass of Oxygen = 16g /mole

mass of the empirical formule = 3*12 + 4*1 + 4*16 = 104

5) Calculate the molecular formula

mass of molecular formule / mass of empirical formula = n

We have to multiply the empirical formula by n to get the molecular formula.

104 / 104 = 1 = n

This means the empirical formula = molecular formula = C3H4O4

4 0
3 years ago
HELP HURRY‼️‼️‼️<br> FAST
lesya692 [45]

I believe the answer is D

8 0
2 years ago
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Ammonia (nh3) is widely used as a fertilizer and in many household cleaners. how much ammonia is produced when 6.64 mol of hydro
olga55 [171]
N₂ + 3H₂ ⇒ 2NH₃

doesnt matterN₂ + 6.64H₂ ⇒ 2NH₃

(6.64H₂/3H₂) x (2NH₃) =4.4266667

rounded to sig figs= 4.43

5 0
3 years ago
For an endothermic reaction, how will the value for Keq change when the temperature is increased?
Nataly [62]
I put the answer <em>C: Keq will increase</em>, on PLATO. Hope this works for you!
4 0
3 years ago
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Why rock from earth cannot be used to determine earth age<br>​
Reptile [31]

Answer:So far scientists have not found a way to determine the exact age of the Earth directly from Earth rocks because Earth's oldest rocks have been recycled and destroyed by the process of plate tectonics. If there are any of Earth's primordial rocks left in their original state, they have not yet been found.

Explanation:

5 0
3 years ago
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