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RoseWind [281]
4 years ago
12

Describe 2 physical and 2 chemical changes involved in cooking Please answer quick!!!

Chemistry
1 answer:
pshichka [43]4 years ago
7 0

Answer: theres alot let me explain...

Explanation:

Protein denaturation is what makes eggs solidify, collagen break down and convert to gelatin in slow-cooked meat, fish and chicken become more opaque, and all meats firm up and change color. This is primarily achieved by applying heat, but can also occur in the presence of acidic and basic ingredients.

The Maillard reaction is the primary effect taking place in “browning”, and produces more flavor compounds, resulting in more complex flavors in food that we generally find enjoyable. It involves reaction between amino acids (proteins) and a certain class of sugars called reducing sugars — mostly the monosaccharides, such as glucose and fructose.

Caramelization is a secondary browning effect that occurs in foods with sugar content, even though all browning is often referred to as “caramelizing”. It mostly takes place at higher temperatures than Maillard reaction (with the notable exception of fructose).

Pyrolysis, or thermal decomposition (chemical breakdown) begins at higher temperatures. While caramelization is technically in this category, the main effect of this reaction is carbonization. This is what we generally mean when we talk about “burning” food, even though no combustion has taken place. It’s also what happens when we cause oil to smoke and darken. In small, controlled amounts, this can still provide desirable flavors, such as char on the outside of meat and contributing to “wok hei” in stir frying — the latter of which does involve some combustion.

Acid-base reactions produce carbon dioxide, which creates the rise in quick breads such as biscuits. These often occur at room temperature, but some also don’t occur until higher temperatures — which is how “double-acting” baking powder works.

Gluten formation occurs when you mix flour and water, resulting in stretchy doughs and fluffy baked goods. This occurs easily at room temperature.

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How many particles are in 3.2 mole of neon gas
Cerrena [4.2K]

There are 1.93 x 10²⁴ particles

<h3>Further explanation</h3>

Given

3.2 moles of Neon gas

Required

Number of particles

Solution

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

<em>1 mol = 6.02.10²³ particles </em>

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

So the number of particles for 3.2 moles :

N = 3.2 x 6.02.10²³

N = 1.93 x 10²⁴

or

we can describe it using Avogadro's number conversion factor

\tt 3.2~moles\times \dfrac{6.02\times 10^{23}}{1~mole}=1.93\times 10^{24}

7 0
3 years ago
Ammonium phosphate ((NH4)3 PO4) is an important ingredient to many fertilizers. It can be made by reacting phosphoric acid (H3 P
lara31 [8.8K]

Answer:

15.35 g of (NH₄)₃PO₄

Explanation:

First we need to look at the chemical reaction:

3 NH₃ + H₃PO₄ → (NH₄)₃PO₄

Now we calculate the number of moles of ammonia (NH₃):

number of moles = mass / molecular wight

number of moles = 5.24 / 17 = 0.308 moles of NH₃

Now from the chemical reaction we devise the following reasoning:

if         3 moles of NH₃ are produce 1 mole of (NH₄)₃PO₄

then   0.308 moles of NH₃ are produce X moles of (NH₄)₃PO₄

X = (0.308 × 1) / 3 = 0.103 moles of (NH₄)₃PO₄

mass = number of moles × molecular wight

mass = 0.103 × 149 = 15.35 g of (NH₄)₃PO₄

4 0
3 years ago
Can you tell me name of Chemicals in food?​
Artyom0805 [142]

Answer:

Guar gum

sodium nitrite

artificial food colorings

monosodium glutamate

etc

6 0
3 years ago
What is the net Ionic equation of HClO4(aq)+ NaOH(aq) = H2O(l)+ NaClO4(aq)
uranmaximum [27]
H^+(aq) + OH^-(aq) ---> H2O(l) 

<span>Na^+ and ClO4^- are the spectator ions.</span>
7 0
3 years ago
How many moles of oxygen atoms are in 7.9E-1 moles of CO_2
Ilya [14]

Answer:

The number of moles of O atom in (7.9\times10^{-1}) mol of CO_{2} = 1.6

Explanation:

1 molecule of CO_{2} contains 2 atoms of O

So, (6.023\times 10^{23}) molecules of  CO_{2} contains (2\times6.023\times10^{23}) atoms of O.

We know that 1 mol of an atom/molecule/ion represents 6.023\times10^{23} numbers of atoms/molecules/ions respectively.

So, (6.023\times 10^{23}) molecules of  CO_{2} is equal to 1 mol of CO_{2}.

(2\times6.023\times10^{23}) atoms of O is equal to 2 moles of O atom.

Hence, 1 mol of CO_{2} contains 2 moles of O atom.

Therefore, (7.9\times10^{-1}) mol of CO_{2} contains (2\times7.9\times10^{-1}) moles of O atom or 1.6 moles of O atom.

3 0
3 years ago
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