Answer:
Explanation:
Given
Initial velocity of first billiard ball
Initial velocity of second billiard ball
After collision first ball comes to rest
suppose m is the mass of both the balls
Conserving momentum to get the speed of second ball after collision
Initial momentum
Final momentum
where and
are the speed of first and second ball respectively
thus speed of second ball after collision is equal to speed of first ball before collision
Answer:
6.49707626552 m/s
4.45147808359 m
1.46212197842 s
Explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration
g = Acceleration due to gravity = 9.81 m/s²
The speed with which Sam releases the ball is 6.49707626552 m/s
The ball reaches a height of 2.3+2.15147808359 = 4.45147808359 m
Distance to his head from the maximum height is 4.45147808359-1.83 = 2.62147808359 m
Time taken to go down to his head is 0.731060989212 seconds from the maximum height
Time taken from the moment the ball left his head height = 0.731060989212+0.731060989212 = 1.46212197842 s