**Answer:**

Power = 47.0 Watt

**Explanation:**

As we know that friction force is given by

now we have

m = 6.0 kg

now we have

now since we need to find the rate of work done by friction force

so we can say rate of work done is power due to friction force

so it is given as

The acceleration due to gravity is **g/4**

The acceleration above the earth surface is given by the relation

g^'=gr^2/〖(h+r)〗^2

Since the satellite orbits the earth in a orbit of radius equal to earth radius, therefore

g^'=(gr^2)/〖(r+r)〗^2 =g/4

Thus the acceleration due to gravity on the satellite is **g/4. **

**Answer:**

**16m**

**Explanation:**

Given parameters:

Time = 4s

Initial velocity = 0m/s

Acceleration = 2m/s²

Unknown:

How far will the body move = ?

Solution:

To solve this problem, we use the expression below:

s = ut + at²

s is the distance

u is the initial velocity

t is the time

a is the acceleration

s = (0 x 4) + ( x 2 x 4²) = **16m**