Jeff has 10 grams of water and 10 grams of vegetable oil in separate containers. Both liquids have a temperature of 24°C. Jeff h
2 answers:
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Answer:
= 1220 nm
= 1.22 μm
Explanation:
given data:
wavelength
distance of screen from slits D = 3 m
1st order bright fringe is 4.84 mm
condition for 1 st bright is
---( 1)
and
= 0.0924 degrees
plug theta value in equation 1 we get
condition for 1 st dark fringe
= 2λ since from eq (1)
= 1220 nm
= 1.22 μm