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3 years ago

14

A runner starts at point A, runs around a 1-mile track and finishes the run back at point A. Which of the following statements i

s true?

1 answer:

babymother [125]3 years ago

4 0

I don’t see any statements

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An atom’s emission of light with a specific amount of energy confirms that

laila [671]

<span>An atom’s emission of light with a specific amount of energy confirms that </span><span>electrons emit and absorb energy based on their position around the nucleus.

The light emitted from an electron is a result of the electron's quantum jumps/leaps ( atomic electron transitions ) to and from different energy levels.</span>

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3 years ago

Read 2 more answers

When the rocket launched the astronauts aboard experienced an acceleration of 32 m/s^2. If one of the astronauts had a mass of 6

sergij07 [2.7K]

Answer:

The question is somewhat vague in that acceleration is not exactly defined:

Usually a = (v2 - v1) / t which would imply that

a = 32 / g = 32 / 9.8 = 3.27 the acceleration due to change in speed of the rocket

One can also say that the astronaut experiences an acceleration of 9.8 m/s^2 just by being motionless on the surface of the earth.

Then a = (32 - 9.8) / 9.8 = 2.27 due to the acceleration of the rocket

If we assume the first condition then

F = 65 kg * 3.27 * 9.8 m/s^2 = 2083 N

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2 years ago

A truck starts off 151 miles directly north from the city of Hartville. It travels due east at a speed of 41 miles per hour. Aft

Bess [88]

Answer:

9.51

Explanation:

The distance s is given by:

$s(t) = \sqrt{151^2 + (vt)^2}$

The change in distance is given by the time derivative of s:

$\frac{ds}{dt} = \frac{v^2t}{\sqrt{151^2 + (vt)^2}}$

For the time t you solve the equation of distance x for time:

$x = vt => t = \frac{x}{v}$

Plugging in for t:

$\frac{ds}{dt}(t=\frac{x}{v})=\frac{vx }{\sqrt{151^2 + x^2}}=9.51$

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3 years ago

How does gay-lussac's law apply to everyday life?

vladimir2022 [97]

Gay-Lussac's Law shows the direct relationship between pressure and temperature for an ideal gas with constant volume. Mathematically it is
$\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$

This particular has a lot of application in our everyday life. In cooking, for example, we apply this concept when using a pressure cooker. We increase/decrease the temperature to meet the right amount of pressure.

In addition, knowing that pressure increases when temperature does can help you with road safety. Knowing that temperature affects heat directly, we must be careful in making sure that tires are not overheated or else they explode out of too much pressure inside.

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3 years ago

Unless indicated otherwise, assume the speed of sound in air to be v = 344 m/s. You have a stopped pipe of adjustable length clo

faltersainse [42]

Answer:

Length of pipe $= 0.057$ meter

Explanation:

Speed of a transverse wave on a string

$v = \sqrt{\frac{F}{\mu} }$

where F is the tension in string and $\mu$ is the mass per unit length

Thus,

$\mu = \frac{m}{L}$

Substituting the given values we get -

$\mu = \frac{7.25 * 10^{-3}}{0.62}\\mu = 0.0117 \frac{Kg}{m}$

Speed of a transverse wave on a string

$v = \sqrt{\frac{4510}{0.0117} } \\v = 620.86 \frac{m}{s}$

For third harmonic wave , frequency is equal to

$f = \frac{nv}{2L}$

Substituting the given values, we get -

$f = \frac{3 * 620.86}{2 * 0.62} \\f = 1502.08$

Length of pipe

$L = \frac{nv}{4 f}$

Substituting the given values we get

$n = 1$ for first harmonic wave

$L = \frac{344* 1}{4*1502.08} \\L = 0.057$

Length of pipe $= 0.057$ meter

5 0

3 years ago