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leva [86]
3 years ago
12

1. To describe the length of a classroom, a student should use what? A) centigrams B) centimeters C) kilometers D) meters 2. Whi

ch is a standard metric base unit, correctly matched with what it measures?
A) Kelvin: time B) second: time C) meter: volume D) gram: temperature A tectonic plate near Niihau, an island in Hawaii, grows at an average rate of 11 cm/year. How many centimeters will the plate grow in 2 years?
A) 2 cm B) 11 cm C) 22 cm D) 30 cm The plate near the Artic Ridge is among those with the slower growth rates, moving slightly less than 2.5 cm/year. How much will the plate move in 10 years? A) less than 5 cm B) equal to 25 cm C) less than 25 cm D) greater than 25 cm
Physics
2 answers:
Gemiola [76]3 years ago
7 0
1).  To describe the length of a classroom, a student can use any unit
he feels like using.  Some units will produce ridiculous numbers, though. 
The most convenient numbers will result from using meters or centimeters. 
If the room is, say, 20 feet long, then that's about 0.0061 kilometer, or
about 610 centimeters, or about 6.1 meters.
Meters is probably best.

2).
A). Kelvin: time.       No.  Kelvin is a unit of temperature.
B). second: time    Yes.  Second is a unit of time.
C). meter: volume    No.  Meter is a unit of length or distance.
D). gram: temperature.  No.  Gram is a unit of mass.

3).  A plate near Hawaii grows about 11 cm per year.
So it grows 11 cm in the first year, and another 11 cm in the second year.
The total growth in 2 years is (11cm + 11cm) = 22 cm .

4).  A slower plate in the Arctic moves slightly less than 2.5 cm per year.
It moves ...
slightly less than 2.5 cm in the 1st year
slightly less than 2.5 cm in the 2nd year
slightly less than 2.5 cm in the 3rd year
slightly less than 2.5 cm in the 4th year
slightly less than 2.5 cm in the 5th year
slightly less than 2.5 cm in the 6th year
slightly less than 2.5 cm in the 7th year
slightly less than 2.5 cm in the 8th year
slightly less than 2.5 cm in the 9th year
and
slightly less than 2.5 cm in the 10th year
for a grand total of 
           (slightly less than 2.5 cm x 10) = less than 25 cm in 10 years.

sdas [7]3 years ago
7 0

1 d,   2 b,   3 c,   4 c that is the answer to them

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I'd say that because of gravity and the material made the red giant it's holding all the material together to be in one piece years and years to come.

Hope that helped! <3 ^-^
6 0
4 years ago
In Ancient Greece, athletes competing in the long jump used handheld weights called halteres to lengthen their jumps. You are a
katovenus [111]

The halter add the distance to the jump in meters is 0.55 m.

<h3>What is projectile?</h3>

When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion is called the projectile.

The magnitude of velocity u =10.3 m/s, angle of jumping θ = 22.8 degrees.

Components of velocity in x and y direction are

Vx = 10.3 cos 22.8 = 9.5 m/s

Vy = 10.3 sin 22.8 = 4 m/s

Maximum Range of athlete achieved using halter is given by

R = u²sin2θ /g

where, u = initial velocity, θ is the angle of projection and g is the gravitational acceleration.

Substituting the values, we get

R = (10.3)² sin(2 x 22.8 °) / 2 x 9.81

R = 7.75m

At the peak of jump you throw two 5.5 kg masses horizontally behind you such that their velocity is zero in the ground's reference frame.

The momentum is conserved in this situation,

(M+2m)Vxo =MVx'

Vx' = (M+2m)/M x Vxo'

Change in x component of velocity ΔVx = Vx' -Vxo

Vxo = 2m/M x Vx

Vxo = 2 x 5.5 /78 x 9.5

Vxo = 1.34 s

Maximum height gained when final velocity is zero

Vy = 0 = Vyo -gt

time t = Vyo/g = 4/9.8 = 0.41s'

Increase in range by using of halters is

ΔR = ΔVx' x t

ΔR = 1.34 x 0.41

ΔR =0.55m

Thus, the halter add the distance to the jump in meters is 0.55 m.

Learn more about projectile.

brainly.com/question/11422992

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3 0
2 years ago
A 500g cart moving at 0.25 m/s collides and sticks to a stationary 750g cart. How fast do the two carts
Tresset [83]

Answer:

0.1 m/s

Explanation:

Please see attached photo for explanation.

Mass of 1st cart (m₁) = 500 g

Initial velocity of 1st cart (u₁) = 0.25 m/s

Mass of 2nd cart (m₂) = 750 g

Initial velocity of 2nd cart (u₂) = 0 m/s

Velocity (v) after collision =.?

m₁u₁ + m₂u₂ = v(m₁ + m₂)

(500 × 0.25) + (750 × 0) = v(500 + 750)

125 + 0 = v(1250)

125 = 1250v

Divide both side by 1250

v = 125 / 1250

v = 0.1 m/s

Thus, the two cart will move with a velocity of 0.1 m/s after collision.

3 0
3 years ago
What is most likely the amount of energy available at a trophic level of primary consumers if the amount of energy available to
docker41 [41]

Answer:

200 kilocalories

Explanation:

6 0
3 years ago
________ In many cartoon shows, a character runs off a cliff, realizes his predicament, and lets out a scream. He continues to s
IrinaVladis [17]

Answer:

Here the source is moving away from the observer so frequency will be smaller than the actual frequency and since the speed is increasing so the frequency is decreasing with time so correct answer is

D) lower than the original pitch and decreasing as he falls.

Explanation:

As we know by the Doppler's effect of sound we have

so we will have

f = f_o(\frac{v}{v + v_s})

so here when source moves away from the observer with a some speed then the frequency of the sound observed by the observer is smaller than the actual frequency

Here we know that the speed of the source is increasing with time as the source is falling under gravity

So we can say that the pitch of the sound will decrease with time

4 0
4 years ago
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