Answer:
-245.7°C es la temperatura del gas bajo 100 torr
Explanation:
Para resolver esta pregunta debemos hacer uso de la ley de Boyle que establece que la presión de un gas es directamente proporcional a la temperatura de este cuando el volumen permanece constante. La ecuación es:
P1T2 = P2T1
<em>Donde P es presión y T temperatura absoluta del estado inicial, 1, y final, 2.</em>
<em />
Reemplazando:
P1 = 1000torr
T2 = ? -Incógnita-
P2 = 100torr
T1 = 273K -Temperatura del hielo fundido = 0°C = 273K
1000torrT2 = 100torr273
T2 = 27.3K
27.3K - 273 =
<h3>-245.7°C es la temperatura del gas bajo 100 torr</h3>
<em />
Answer:
Ksp = 2.74 x 10⁻⁵
Explanation:
The solubility equilibrium for Ca(OH)₂ is the following:
Ca(OH)₂(s) ⇄ Ca²⁺(aq) + 2 OH⁻(aq)
I 0 0
C + s + 2s
E s 2s
According to the ICE table, the expression for the solubility product constant (Kps) is:
Ksp = [Ca²⁺] x ([OH⁻])² = s x (2s)² = 4s³
Then, we calculate Ksp from the solubility value (s):
s = 0.019 M
⇒ Ksp = 4s³ = 4 x (0.019)³ = 2.74 x 10⁻⁵
Answer:
Oxygen and Chlorine
Explanation:
Covalent bonds involve the sharing of electrons between nonmetals.
So I believe you are supposed to take notes based on the guiding questions (the questions on the side).
Answer:
Explanation:
2NO₂ ⇌ N₂O₄
E/mol·L⁻¹: 0.058 0.012
K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6}
\\\\
\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}
