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Basile [38]
3 years ago
9

Understanding Acceleration: Remember, acceleration is speeding up, slowing down, or changing direction.

Chemistry
2 answers:
Georgia [21]3 years ago
6 0

Answer:

<h2>∞∞∞∞∞∞║⊕║Hello Person║⊕║∞∞∞∞∞∞</h2>

Your answer should be:

<em>1. No </em>

<em>2. Yes</em>

<em>3. No</em>

<em>4. Yes</em>

<em>5. No</em>

Explanation:

I hope this answered your question.

<em>Brainliest would be appreciated! </em>

<em>Have a wonderful day!</em>

s2008m [1.1K]3 years ago
6 0

Answer:

I dont know

Explanation:

ONLY HEAR FOR POINts

You might be interested in
Someone help 6th grade science i will give brainliest
patriot [66]
I believe the answer is C
3 0
3 years ago
Read 2 more answers
Sample A: 300 mL of 1M sodium chloride
yarga [219]

Answer:

sample B contains the larger density

Explanation:

Given;

volume of sample A, V = 300 mL = 0.3 L

Molarity of sample A, C = 1 M

volume of sample B, V = 145 mL = 0.145 L

Molarity of sample B, C = 1.5 M

molecular mass of sodium chloride, Nacl = 23 + 35.5 = 58.5 g/mol

Molarity is given as;

C = \frac{moles \ of \ solute, \ mol}{liters \ of \ solvent} \\\\Moles \ of \ solute \ for \ sample \ A = 1 \times 0.3 = 0.3 \ mol\\\\Moles \ of \ solute \ for \ sample \ B = 1.5 \times 0.145 = 0.2175 \ mol

The reacting mass for sample A = 0.3mol x  58.5 g/mol = 17.55 g

The reacting mass for sample B = 0.2175 mol x 58.5 g/mol = 12.72 g

The density of sample A  = \frac{mass}{volume} = \frac{17.55}{0.3} = 58.5 \ g/L

The density of sample B = \frac{mass}{volume} = \frac{12.72}{0.145} = 87.72 \ g/L

Therefore, sample B contains the larger density

5 0
3 years ago
If 16.00 g of O₂ reacts with 80.00 g NO, how many the excess reactant are left over? (enter only the value, round to whole numbe
pishuonlain [190]

Answer:

50

Explanation:

We will need a balanced equation with masses, moles, and molar masses of the compounds involved.

1. Gather all the information in one place with molar masses above the formulas and masses below them.  

Mᵣ:           30.01     32.00   46.01

               2NO   +   O₂ ⟶ 2NO₂

Mass/g:  80.00     16.00

2. Calculate the moles of each reactant  

\text{moles of NO} = \text{80.00 g NO} \times \dfrac{\text{1 mol NO}}{\text{30.01 g NO}} = \text{2.666 mol NO}\\\\\text{moles of O}_{2} = \text{16.00 g O}_{2} \times \dfrac{\text{1 mol O}_{2}}{\text{32.00 g O}_{2}} = \text{0.5000 mol O}_{2}

3. Calculate the moles of NO₂ we can obtain from each reactant

From NO:

The molar ratio is 2 mol NO₂:2 mol NO

\text{Moles of NO}_{2} = \text{2.333 mol NO} \times \dfrac{\text{2 mol NO}_{2}}{\text{2 mol NO}} = \text{2.333 mol NO}_{2}

From O₂:

The molar ratio is 2 mol NO₂:1 mol O₂

\text{Moles of NO}_{2} =  \text{0.5000 mol O}_{2}\times \dfrac{\text{2 mol NO}_{2}}{\text{1 mol Cl}_{2}} = \text{1.000 mol NO}_{2}

4. Identify the limiting and excess reactants

The limiting reactant is O₂ because it gives the smaller amount of NO₂.

The excess reactant is NO.

5. Mass of excess reactant

(a) Moles of NO reacted

The molar ratio is 2 mol NO:1 mol O₂

\text{Moles reacted} = \text{0.500 mol O}_{2} \times \dfrac{\text{2 mol NO}}{\text{1 mol O}_{2}} = \text{1.000 mol NO}

(b) Mass of NO reacted

\text{Mass reacted} = \text{1.000 mol NO} \times \dfrac{\text{30.01 g NO}}{\text{1 mol NO}} = \text{30.01 g NO}

(c) Mass of NO remaining

Mass remaining = original mass – mass reacted = (80.00 - 30.01) g = 50 g NO

5 0
3 years ago
The coin of silver (ag) having 8.5 grams weight.calculate the number of moles of silver in coin
AfilCa [17]

0.0788 will be the number of moles of silver in coin.

<h3><u>How to find the number of moles?</u></h3>

A mole is the mass of a material made up of the same number of fundamental components. Atoms in a 12 gram example are identical to 12C. Depending on the material, the fundamental units may be molecules, atoms, or formula units.

A mole fraction shows how many chemical elements are present. The value of 6.023 x 10²³ is equivalent to one mole of any material (Avagadro's number). It can be used to quantify the chemical reaction's byproducts. The symbol for the unit is mol.

The number of moles formula is denoted by the following expression:

Number of moles = Mass of substance/mass of one mole

To view more about number of moles, refer to:

brainly.com/question/14080043

#SPJ4

6 0
2 years ago
Explain how an ionic compound forms between Na &amp; N.
maxonik [38]

Answer:

Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N

Explanation:

Three Na atom(s) each lose one electron, forming three Na+ ions. One N atom gains three electrons, forming a N^-3 ion. The ions attract, forming Na3N.

Ionic bond:

It is the bond which is formed by the transfer of electron from one atom to the atom of another element.  

Both bonded atoms have very large electronegativity difference. The atom with large electronegativity value accept the electron from other with smaller value of electronegativity.

For example:

Na₃N is ionic compound. The electronegativity of is 3.04 and for sodium is 0.93. There is large difference is present. That's why electron from sodium is transfer to the nitrogen. Sodium becomes positive and nitrogen becomes negative ion.

One nitrogen atom required three electrons to complete the octet while sodium have one valance electron that's why three sodium atoms combine with one nitrogen atom.

5 0
3 years ago
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