1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lesantik [10]
3 years ago
13

One kilogram of the explosive TNT supplies explosive energy of about 4.2×10^6 J. Let's see what that energy can achieve in lifti

ng objects from Earth's surface to altitudes of hundreds of kilometers. We approach the issue through gravitational potential energy.
a. Assume the acceleration due to gravity is constant at g = 9.81 m/s2 from Earth's surface up to an altitude of 630 km above the surface. (A satellite at such an altitude would be in a "low Earth orbit.") What is the gravitational potential energy, in joules, of a 1.0-kg object at that altitude, taking the reference level for gravitational potential energy (U -0) at Earth's surface?
b. How many kilograms of TNT would need to be exploded, if the released energy were somehow used to raise a 10-kg object from Earth's surface to an altitude of 630 km at 100% efficiency, assuming constant g?
c. Again take the reference level at Earth's surface. Earth's radius and mass are 6.38x103 km and 5.97x1024 kg, respectively. Now calculate the gravitational potential energy, in joules, of a 1 0-kg object at an altitude of 630 km without assuming constant 25%
d. Without assuming constant g, how many kilograms of TNT would need to be exploded, if the released energy were somehow used to raise a 1-0-kg object from Earth's surface to an altitude of 630 km at 100% efficiency?
Physics
1 answer:
makkiz [27]3 years ago
3 0

Answer:

4,0000

Explanation:

You might be interested in
A mass that weighs 10 lb stretches a spring 2.4 in. It rests in a liquid which imparts a dampening force of 4 pounds when the ve
forsale [732]

Answer:

The solution is attached in the pictures below

Explanation:

5 0
3 years ago
If a body travels half its total path in the last 1.50 s of its fall from rest, find the total time of its fall (in seconds).
svetoff [14.1K]

Answer:

time to fall is 3.914 seconds

Explanation:

given data

half distance time = 1.50 s

to find out

find the total time of its fall

solution

we consider here s is total distance

so equation of motion for distance

s = ut + 0.5 × at²   .........1

here s is distance and u is initial speed that is 0 and a is acceleration due to gravity = 9.8 and t is time

so for last 1.5 sec distance is 0.5 of its distance so equation will be

0.5 s = 0 + 0.5 × (9.8) × ( t - 1.5)²     ........................1

and

velocity will be

v = u + at

so velocity v = 0+ 9.8(t-1.5)    ..................2

so first we find time

0.5 × (9.8) × ( t - 1.5)² = 9.8(t-1.5)  + 0.5 ( 9.8)

solve and we get t

t = 3.37 s

so time to fall is 3.914 seconds

6 0
4 years ago
A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 1
Bumek [7]

Answer:

202.8m

Explanation:

Given that A pirate fires his cannon parallel to the water but 3.5 m above the water. The cannonball leaves the cannon with a velocity of 120 m/s. He misses his target and the cannonball splashes into the briny deep.

First calculate the total time travelled by using the second equation of motion

h = Ut + 1/2gt^2

Let assume that u = 0

And h = 3.5

Substitute all the parameters into the formula

3.5 = 1/2 × 9.8 × t^2

3.5 = 4.9t^2

t^2 = 3.5/4.9

t^2 = 0.7

t = 0.845s

To know how far the cannonball travel, let's use the equation

S = UT + 1/2at^2

But acceleration a = 0

T = 2t

T = 1.69s

S = 120 × 1.69

S = 202.834 m

Therefore, the distance travelled by the cannon ball is approximately 202.8m.

4 0
3 years ago
An experimental tungsten light bulb filament has a length of 5 cm and a diameter of 0.074 cm. The filament is basically just a w
adell [148]

Answer:

power emitted is 1.75 W

Explanation:

given data

length l = 5 cm = 5 ×10^{-2} m

diameter d = 0.074 cm = 74 ×10^{-5} m

total filament emissivity = 0.300

temperature = 3068 K

to find out

power emitted

solution

we find first area that is π×d×L

area = π×d×L

area = π×74 ×10^{-5}×5 ×10^{-2}

area = 1162.3892  ×10^{-5} m²

so here power emitted  is express as

power emitted  = E × σ × area × (temperature)^4

put here all value

power emitted  = 0.300× 5.67 × 1162.3892  ×10^{-5}  × (3068)^4

power emitted = 1.75 W

5 0
3 years ago
A large crane consists of a 20 m, 3,000 kg arm that extends horizontally on top of a vertical tower. The arm extends 15 m toward
Anni [7]

Answer:

m=18000kg

Explanation:

From the question we are told that:

Crane Length l=20m

Crane Mass m_a=3000kg

Arm extension at lifting end l_l=15m

Arm extension at counter weight end l_c=5m

Load M_l=5000kg

Generally the equation for Torque Balance is mathematically given by

T_1 *l_c-(m_a*g) *l_c-(T_2)*l_l=0

mg*5 *-(3000*9.8) *5-(5000*9.8)*15=0

m=18000kg

7 0
3 years ago
Other questions:
  • Tala wants to create a sound echo. She can create the echo using a pane of glass or a carpet square. Which one does she choose?
    14·1 answer
  • A damped oscillator is released from rest with an initial displacement of 10.00 cm. At the end of the first complete oscillation
    11·1 answer
  • Sound waves are mechanical waves in which the particles in the medium vibrate in a direction parallel to the direction of energy
    9·1 answer
  • Party hearing. As the number of people at a party increases, you must raise your voice for a listener to hear you against the ba
    14·1 answer
  • What are laws of newton
    9·2 answers
  • A sound wave travels through water. What best describes the direction of the water particles? The water particles move perpendic
    7·1 answer
  • How are wavelength and frequency related for a wave moving at a constant speed?
    7·1 answer
  • An object is swung in a horizontal circle on a length of string that is 0.93 m long. Its acceleration is 26.36 m/s2. What is the
    13·1 answer
  • The current in a resistor is 2.0 A, and its power is 78 W. What is the voltage?
    14·1 answer
  • An oil has a kinematic viscosity of 1.25 × 10^-4 and a specific gravity of 0.8. What is the viscosity of this oil in SI unit of
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!