Multiply 12 x 12 which is 144. And then you divide that by 6 and you get 24
4(-2)-3 = -8-3 = -11
Answer: -11
Answer:
(1,1)
Step-by-step explanation:
The choices are not visible, however are unnecessary to solve this problem.
Given y = 3x - 2 and y = -2x + 3
[Set them equal to each other]
3x - 2 = -2x + 3
[Find x]
3x + 2x - 2 = 3
3x + 2x = 5
5x = 5
x = 1
[Plug x = 1 to both equations to check and find y]
y = 3x - 2
y = 3(1) - 2 = 3 - 2 = 1
y = -2x + 3
y = -2(1) + 3 = -2 + 3 = 1
Both are equal to y = 1 when x = 1
The point is then: (1,1)
Given:
The complex number is:

To find:
The argument of the given complex number.
Solution:
If a complex number is
, then the argument of the complex number is:

We have,

Here,
and
. So, the argument of the given complex number is:




Therefore, the argument of the given complex number is
.