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olga nikolaevna [1]
4 years ago
14

Superman attempts to drink water through a very long vertical straw. With his great strength, he achieves maximum possible sucti

on. The walls of the tubular straw don't collapse.
(a) Find the maximum height through which he can lift the water.
m
(b) Still thirsty, the Man of Steel repeats his attempt on the Moon, which has no atmosphere. Find the difference between the water levels inside and outside the straw.
m
Physics
1 answer:
Stells [14]4 years ago
5 0

Answer:

10.32874 m

Explanation:

P_a = Atmospheric pressure = 101325 Pa

g = Acceleration due to gravity = 9.81 m/s²

h = Height of water

\rho = Density of water = 1000 kg/m³

If the walls of the tube do not collapse that means that maximum pressure inside will be the atmospheric pressure

Atmospheric pressure is given by

P_a=\rho gh\\\Rightarrow h=\dfrac{P_a}{\rho g}\\\Rightarrow h=\dfrac{101325}{1000\times 9.81}\\\Rightarrow h=10.32874\ m

The maximum height to which Superman can lift the water is 10.32874 m

On the Moon there is no atmosphere so no atmospheric pressure which means when the straw is placed in water water will not rise in the tube.

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1) what is the potential energy at the end of the loop?
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The potential energy at the end of the loop is equal to 0.3407 Joules.

<u>Given the following data:</u>

  • Mass of rock = 102.16 g to kg = 0.10216 kilogram.
  • Height of the loop = 34 cm to m = 0.34 meter.
  • Acceleration due to gravity = 9.8 m/s^2

<h3>What is potential energy?</h3>

Potential energy (P.E) refers to the energy that is possessed by an object due to its position (height) above planet Earth.

Mathematically, potential energy (P.E) is given by this formula;

P.E = mgh

<u>Where:</u>

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Substituting the given parameters into the formula, we have;

P.E = 0.10216 \times 9.81 \times 0.34

P.E = 0.3407 Joules.

<h3>What is kinetic energy?</h3>

Kinetic energy (K.E) refers to an energy that is possessed by a physical object due to its motion.

Mathematically, kinetic energy (K.E) is given by this formula;

K.E = \frac{1}{2} MV^2

<u>Note:</u> You'll have to calculate the velocity from the distance traveled by the car and photogate time in your experiment.

Based on the law of conservation of energy, we can deduce the following points:

  • Potential energy (P.E) is <u>highest</u> at the top of the loop while kinetic energy (K.E) is <u>lowest</u>.
  • Kinetic energy (K.E) is <u>highest</u> underneath the loop while potential energy (P.E) is <u>lowest</u>.

Read more on potential energy here: brainly.com/question/8664733

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2 years ago
Two identical particles, each with a mass of 4.5 mg and a charge of 30 nC, are moving directly toward each other with equal spee
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Answer:

   r₁ = 20.5 cm

Explanation:

In this exercise we can use the conservation of energy

the gravitational power energy is always attractive, the electrical power energy is repulsive if the charges are of the same sign

starting point.

        Em₀ = U_g + U_e + K = -G \frac{m_1m_2}{r} +k \frac{q_1q_2}{r} - 2 ( \frac{1}{2}  m v^2)

the two in the kinetic energy is because they are two particles

final point. When it is detained

        Em_f = U_g + U_e = -G \frac{m_1m_2}{r_1} + k \frac{q_1q_2}{r_1}

the energy is conserved

        Em₀ = em_f

the charges and masses of the two particles are equal

         -G \frac{m^2}{r} + k \frac{q^2}{r} + m v^2 = - G \frac{m^2}{r_1} + k \frac{q^2}{r_1}        

         

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    -5.4 10⁻¹⁵ + 3.24 10⁻⁵ - 7.2 10⁻⁵ = -1.35 10⁻¹⁵ / r₁  + 8.1 10⁻⁶ / r₁

We can see that the terms that correspond to the gravitational potential energy are much smaller than the terms of the electric power, which is why we depress them.

      3.24 10⁻⁵ - 7.2 10⁻⁵ =  8.1 10⁻⁶ / r₁

      -3.96 10⁻⁵ = 8.1 10⁻⁶ / r₁

      r₁ = 8.1 10⁻⁶ /3.96 10⁻⁵

      r₁ = 2.045 10⁻¹ m

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