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Svetach [21]
3 years ago
9

Which answer shows a balanced nuclear equation for the beta decay of potassium-42?

Physics
2 answers:
aev [14]3 years ago
5 0

Potassium undergoes beta (minus) decay to produce an electron and a calcium nucleus.

KIM [24]3 years ago
5 0

Answer:

_{19}^{42}K --> _{20}^{42}Ca + \beta + \nu

Explanation:

In Beta decay unstable nuclei will convert into stable nuclei by converting its neutron into an electron and a proton.

this process is given as

n --> p + \beta + \nu

so in this process mass number will remain same but atomic number will increased by 1

So the new nuclei is of higher atomic number

So we will have

_{19}^{42}K --> _{20}^{42}Ca + \beta + \nu

so above is the nuclear reaction

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Discuss how a photon (aka the light particle) can be affected by gravity despite being massless.
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Explanation:

Light is clearly affected by gravity, just think about a black hole, but light supposedly has no mass and gravity only affects objects with mass. On the other hand, if light does have mass then doesn't mass become infinitely larger the closer to the speed of light an object travels.

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What is the energy of work done lifting 2kg mass rocket to a height of 130 m
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lisabon 2012 [21]

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Explanation:

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3 years ago
A 133 kg horizontal platform is a uniform disk of radius 1.95 m and can rotate about the vertical axis through its center. A 62.
cupoosta [38]

Answer:

The moment of inertia of the system is  I = 400.5 \ kg \cdot m^2

Explanation:

From the question we are told that

    The mass of the platform is  m =  133\ kg

     The  radius of the  platform is  r = 1.95 m

     The mass of the person is m_p  =  62.7 \ kg

     The position of the person from the center is  d =  1.19 \ m

       The mass of the dog is m_D  =  28.5 \ kg

     The position of the dog from the center is  D = 1.45 \ m

   

Generally the moment of inertia of the platform with respect to its axis is  mathematically represented as

       I_p  =  \frac{m r^2}{2}

The  moment of inertia of the person with respect to the axis is mathematically represented as

        I_z  =  m_p* d^2

The  moment of inertia of the dog with respect to the axis is mathematically represented as

       I_D =  m_d *  D^2

So the moment of inertia of the system about the axis  is mathematically evaluated as

        I  = I_p + I_z + I_D

=>      I = \frac{mr^2}{2}  +  m_p * d^2 +  m_d * D^2

substituting values  

            I = \frac{(133) * (1.95)^2}{2}  +  (62.7) * (1.19)^2 +  (28.5) * (1.45)^2

          I = 400.5 \ kg \cdot m^2

8 0
3 years ago
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