First we need to find the voltage difference between the initial and final location of the electron.
Since the electron travelled for a distance d=5 m in an uniform electric field of intensity E=300 N/C, the voltage difference between the final and initial location is
![\Delta V= Ed=(300 N/C)(5 m)=1500 V](https://tex.z-dn.net/?f=%5CDelta%20V%3D%20Ed%3D%28300%20N%2FC%29%285%20m%29%3D1500%20V)
And then, we can calculate the change in potential energy of the electron, which is the product between the charge of the electron and the voltage difference:
![\Delta U = q\Delta V=(-1.6 \cdot 10^{-19}C)(1500 V)=-2.4 \cdot 10^{-16}J](https://tex.z-dn.net/?f=%5CDelta%20U%20%3D%20q%5CDelta%20V%3D%28-1.6%20%5Ccdot%2010%5E%7B-19%7DC%29%281500%20V%29%3D-2.4%20%5Ccdot%2010%5E%7B-16%7DJ)
And the negative sign is due to the fact that we assumed the electron traveled in the natural direction of the electric field, so traveling from a point at lower voltage to a point at higher voltage (the sign of
![\Delta V](https://tex.z-dn.net/?f=%5CDelta%20V)
is positive), so since it's a negative charge the electron is losing potential energy.
Answer:
1) k = 52 N/m
2) E = 1.0 J
3) ω = 8.1 rad/s
4) v = 1.4 m/s
Though asked for a velocity, we can only supply magnitude (speed) because we don't have enough information to determine direction.
If it happens to be the first time it is at y = - 10 cm after release, the velocity is upward.
Explanation:
Assuming the initial setup is after all transients are eliminated.
kx = mg
k = mg/x = 0.8(9.8) / 0.15
k = 52.26666.... ≈ 52 N/m
E = ½kA² = ½(52)(0.20²) = 1.045333... ≈ 1.0 J
ω = √(k/m) = √(52 / 0.8) = 8.0829... ≈ 8.1 rad/s
½mv² = ½kA² - ½kx²
v = √(k(A² - x²)/m) = √(52(0.20² - 0.10²)/0.8) = 1.39999... ≈ 1.4 m/s
Answer:
In a closed-loop system, matter is used to generate energy, and the energy generated is used to produce matter, and the cycle goes on without end.
Explanation:
A closed-loop system is one in which materials or energy is recycled without end through a production cycle. This means that a raw material is used to produce a finished product, and the finished product at the end of its use cycle is converted back and used as a raw material to produce more of it again. Energy and matter can also be cycled in the same way in an energy and matter closed-loop system, converting matter to energy, and the energy is put back into the production of more of the matter.
Answer:
the beetle's actual distance beneath the surface, d = 3.2 cm
Explanation:
The refractive index for the plastic is about 1.60
For overhead viewing, the expression for refractive index is
n = actual depth / apparent depth
Rearrange for actual depth
actual depth d = n x apparent depth
d = 1.60 x 2.0 cm
d = 3.2 cm