More energy than atoms in a liquid state
This problem is providing the initial volume and pressure of nitrogen in a piston-cylinder system and asks for the final pressure it will have when the volume increases. At the end, the answer turns out to be 2.90 atm.
<h3>Boyle's law</h3>
In chemistry, gas laws are used so as to understand the volume-pressure-temperature-moles behavior in ideal gases and relate different pairs of variables.
In this case, we focus on the Boyle's law as an inversely proportional relationship between both pressure and volume at constant both temperature and moles:

Thus, we solve for the final pressure by dividing both sides by V2:

Hence, we plug in both the initial pressure and volume and final volume in order to calculate the final pressure:

Learn more about ideal gases: brainly.com/question/8711877
Answer:elementary substance
Explanation:
Answer: 2.0 moles of oxygen are needed to completely react with 1.0 mole of CH4 as shown in the balanced equation.
Explanation:
Stoichiometry is a fundamental tool and skill to determine the relative quantities that the chemicals react with. it determines the quantity of one substance to a quantity of another substance or substances. Stoichiometry is relating of one chemical substance to another using a balanced chemical reaction is called stoichiometry. Also, it is very important to predict what will occur and how much is produced through knowing the coefficients of moles of reactants and products.
Mole s defined as the mass of the substance divided by its molar mass.
As shown from the balanced equation every mole of methane(CH4) needs to react with 2.0 moles of oxygen(O2) to produce 1.0 mole of carbon dioxide(CO2) and 2.0 moles of hydrogen peroxide(H2O2).
Explanation:
It is known that rate of effusion of gases are inversely proportional to the square root of their molar masses.
And, half of the helium (1.5 L) effused in 24 hour. So, the rate of effusion of He gas is calculated as follows.
= 0.0625 L/hr
As, molar mass of He is 4 g/mol and molar mass of
is 32 g/ mol.
Now,

= 2.83
or, rate of
= 
Rate of
= 0.022 L/hr.
This means that 0.022 L of
gas effuses in 1 hr
So, time taken for the effusion of 1.5 L of
gas is calculated as follows.
= 68.18 hour
Thus, we can conclude that 68.18 hours will it take for half of the oxygen to effuse through the membrane.