<span>You must balance your equation correctly.
Here is your answer:
294gFeS2 x 1molFeS2/119.99 x 11mols O2/4mols FeS2--> 6.738mol O2
176gO2 x 1mol O2/32gO2 x 4mols FeS2/11mol FeS2--> 2mols FeS2
Now choose the molecule with the lowest amount (Limiting Reagent)
2molsFeS2 x 2molsFe2O3/4molsFeS2 x 159.7g
159.7g Fe2O3 grams produced.</span>
Answer:
Q = mcT ...you can either substitute the molar heat capacity of water in the place of c or the specific heat capacity of water.
Explanation:
Explanation:
Apply the mass of balance as follows.
Rate of accumulation of water within the tank = rate of mass of water entering the tank - rate of mass of water releasing from the tank



[/tex]\frac{dh}{dt} + \frac{0.01}{0.01}h[/tex] = 

+ h = 1
= 1 - h
= dt
= t + C
Given at t = 0 and V = 0
= 0
or, h = 0
-ln(1 - h) = t + C
Initial condition is -ln(1) = 0 + C
C = 0
So, -ln(1 - h) = t
or, t =
........... (1)
(a) Using equation (1) calculate time to fill the tank up to 0.6 meter from the bottom as follows.
t =
t =
= 
= 0.916 seconds
(b) As maximum height of water level in the tank is achieved at steady state that is, t =
.
1 - h = exp (-t)
1 - h = 0
h = 1
Hence, we can conclude that the tank cannot be filled up to 2 meters as maximum height achieved is 1 meter.
Answer:
Explanation:
1 mol of sodium = 23 grams (use the number on your periodic table).
0.7350 mol sodium = x
Cross multiply
1*x = 0.7350 * 23
x = 16.905
You will get slightly less than this, depending on your periodic table. But the method will be the same.
JJ Thompson discovered electrons