This is kinda confusing. I wish u just to a screenshot of the problem but here goes...
Forest at highest latitudes- Hardwood trees/deer, squirrel, foxes
Praries/temperate climate- Mostly small mammals/scrubs/steppes
High humidity/rainfall near equator- Abundant thick vegatation/manny species
No trees/ polar bears/ mosses- 25cm rain/few animals
D. <span>When placed together in pairs for study, no pair of Abert's squirrel and Kaibab squirrel result in offspring.</span>
Answer:
Explanation:
Given data
time=0.530 h
Average velocity Vavg=19.0 km/s
To find
Displacement Δx
Solution
The Formula for average velocity is given as
Given Information:
Mass of sock = 0.23 kg
Stretched length of sock = x = 2.54 cm = 0.0254 m
Required Information:
Spring constant = k = ?
Answer:
Spring constant = k = 88.82 N/m
Explanation:
We know from the Hook's law that
F = kx
Where k is spring constant, F is the applied force and x is length of sock being stretched.
k = F/x
Where F is given by
F = mg
F = 0.23*9.81
F = 2.256 N
So the spring constant is
k = 2.256/0.0254
k = 88.82 N/m
Therefore, the spring constant of the sock is 88.82 N/m
It's called the periodic table because it arranges the elements the into repeating sets known as periods. this is defined by the <span>covalence of an element and the number of electrons i has in its outermost shell. I feel the the Best answer would be B. sorry if im wrong but i hope i helped :)</span>
