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madreJ [45]
3 years ago
10

Answer the following question: Ethanol, C2H5OH, is considered clean fuel because it burns in oxygen to produce carbon dioxide an

d water with few trace pollutants. If 150.0 g of H2O are produced during the combustion of ethanol, how many grams of ethanol were present at the beginning of the reaction?
Chemistry
1 answer:
Delvig [45]3 years ago
7 0

Answer:

127.88 grams of ethanol were present at the beginning of the reaction

Explanation:

Firstly, let's make the combustion reaction:

C₂H₅OH  +  3O₂  →  2CO₂  +  3H₂O

By 1 mol of ethanol, you can make 3 mole of water.

Mole of water = Water mass / Molar mass

150g / 18g/m = 8.3 mole

3 mole of water came from 1 mol of ethanol

8.3 mole came from (8.3 .1)/3 = 2.78 mole of ethanol

Molar mass ethanol = 46 g/m

Mole . molar mass = mass

2.78 m .  46g/m = 127.88 g

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Answer:

2.00 moles of Ni has 1.2 *10^24 atoms

Explanation:

Step 1: Data given

Number of moles Ni = 2.00 moles

Number of Avogadro = 6.022*10^23 /mol

Step 2: Calculate number of atoms

Number of particles (=atoms) = Number of Avogadro *  number of moles

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Number of atoms = 1.2*10^24 atoms

2.00 moles of Ni has 1.2 *10^24 atoms

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Answer:

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