The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.
The heat of vaporization has been the amount of heat required to vaporize 1 gram of liquid.
The heat required for the vaporization has been given as:
<h3 /><h3>Computation for the Heat of vaporization</h3>
The heat of vaporization of water has been given as, 
The mass of water sample has been, 
Substituting the values for the heat energy absorbed, <em>Q:</em>
<em />
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The heat absorbed by the water sample for vaporization has been 6,105 kJ. Thus, option D is correct.
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Answer:
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Answer:
Arrhenius acid & Bronsted-Lowry acid
Explanation:
Aphelion in miles =94290301
Perihelion in miles = 91200281
Explanation:
To convert km in mile we use the multiply the distance in km with 0.62, because there are 0.62 miles in 1 km.
Aphelion in miles = aphelion in km × 0.62
Aphelion in miles = 152081132 × 0.62
Aphelion in miles =94290301
Perihelion in miles = perihelion in km × 0.62
Perihelion in miles = 147097229 × 0.62
Perihelion in miles = 91200281
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conversion of units
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the Percentage yield for the reaction = 48.8%
What is Percentage yield ?
The % ratio of the theoretical yield to the actual yield is known as the percent yield. It is calculated as the theoretical yield multiplied by 100% divided by the experimental yield. The percent yield is 100% if the theoretical and actual yields are equal. Because the real yield is frequently lower than the theoretical value, percent yield is typically lower than 100%. This may be due to incomplete or conflicting reactions or sample loss during recovery. If the percent yield is more than 100%, more sample than expected was retrieved from the reaction.
4 P + 3 O2 = P4O6
moles P = 75.3 g / 30.9738 g/mol= 2.43
moles O2 required = 2.43 x 3 / 4=1.82
actual moles O2 = 38.7 g /32 g/mol=1.21 so O2 is the limiting reactant
theoretical moles P4O6 = 1.21 / 3=0.403
theoretical mass P4O6 = 0.403 mol x 219.895 g/mol=88.6 g
% yield = 43.3 x 100/ 88.6 = 48.8 %
the Percentage yield for the reaction = 48.8%
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