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dalvyx [7]
4 years ago
10

Networks of interconnected wireless devices that are embedded into the physical environment to provide measurements of many poin

ts over large spaces are called:
Physics
1 answer:
bazaltina [42]4 years ago
6 0

Wireless sensor networks

Explanation:

Networks of interconnected wireless devices that are embedded into the physical environment to provide measurements of many points over a large spaces are called Wireless sensor networks.

They are very useful in obtaining real-time data and information about every day life.

  • The internet of things greatly relies on the use of wireless sensor networks in devices and gadgets to better and improve life.
  • They are constantly in use by various organizations and bodies.
  • Wireless sensor networks can be designed to collect specific scientific data or even more.

learn more:

Connecting IoT devices brainly.com/question/11028028

#learnwithBrainly

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Please answer ASAP, and please don't joke around and actually do answer my question. I will give you brainliest if you answer it
hammer [34]

Answer:

30 feet

Explanation:

First off, if they are throwing at 12.0 m/s and it takes 2.5 seconds. It will be the act of multiplication.

12 times 2.5 is 30, because 12 times 2 is 24 plus 12 divided by 2 which is 6 so 24 plus 6 is 30.

8 0
3 years ago
while working out a man performed 2525j of work in 19seconds . what was his power A:132.9w. B:241.5w C 47.975w. D100.5w
Olenka [21]
A: 132.9w because 2525\19 is how much energy transferred per second which is also known as the power
7 0
4 years ago
Read 2 more answers
Quick! how did Daniel hale Williams contribute to science?
My name is Ann [436]
He preformed the first ever successful open heart surgery
3 0
3 years ago
What's the difference between a direct relationship and a positive one?
borishaifa [10]
A positive or direct relationship is one in which the two variables (we will generally call them x and y) move together, that is, they either increase or decrease together. In a negative or indirect relationship, the two variables move in opposite directions, that is, as one increases, the other descremases
5 0
3 years ago
A 4-kg toy car with a speed of 5 m/s collides head-on with a stationary 1-kg car. After the collision, the cars are locked toget
mihalych1998 [28]

Kinetic energy lost in collision is 10 J.

<u>Explanation:</u>

Given,

Mass, m_{1} = 4 kg

Speed, v_{1} = 5 m/s

m_{2} = 1 kg

v_{2} = 0

Speed after collision = 4 m/s

Kinetic energy lost, K×E = ?

During collision, momentum is conserved.

Before collision, the kinetic energy is

\frac{1}{2} m1 (v1)^2 + \frac{1}{2} m2(v2)^2

By plugging in the values we get,

KE = \frac{1}{2} * 4 * (5)^2 + \frac{1}{2} * 1 * (0)^2\\\\KE = \frac{1}{2} * 4 * 25 + 0\\\\

K×E = 50 J

Therefore, kinetic energy before collision is 50 J

Kinetic energy after collision:

KE = \frac{1}{2} (4 + 1) * (4)^2 + KE(lost)

KE = 40J + KE(lost)

Since,

Initial Kinetic energy = Final kinetic energy

50 J = 40 J + K×E(lost)

K×E(lost) = 50 J - 40 J

K×E(lost) = 10 J

Therefore, kinetic energy lost in collision is 10 J.

4 0
4 years ago
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