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goldenfox [79]
4 years ago
13

Please help asap, I have 10min

Chemistry
1 answer:
Grace [21]4 years ago
3 0

Answer:

electrons

Explanation:

because it rotates the nucleus around it

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Ask Your Teacher A 1.04-mole sample of ammonia at 11.0 atm and 25°C in a cylinder fitted with a movable piston expands against a
RUDIKE [14]

Answer:

Explanation:

a) Volume of the gas nRT / P

= 1,04 X 8.3 X 298 / 11 X 10⁵ m³

= 233.85 x 10⁻⁵ m³

= 233 x 10⁻² L

2.33 L

P₁V₁ / T₁ =P₂V₂/T₂

(11 X 2.33) / 298 = (1 X 24.2) / T

T = 281.37 K

= 8.37 degree

b ) w = p x change in volume

= 10⁵ x ( 24.2 - 2.33 ) x 10⁻³ J

= 21.87 X 10² J

2187 J

q  = n x Cp x (25 - 8.37 )

= 1.04 x 35.66x 16.63 J

= 616.65 J

ΔU = Q - W

= 616.65  - 2187 J

= - 1570.35 J

=

=

7 0
3 years ago
Using stoichiometry, determine the mass of powdered drink mix needed to make a 1.0 M solution of 100 mL from C12H22O11
fgiga [73]

Answer:

34.23 g.

Explanation:

<em>Molarity is defined as the no. of moles of a solute per 1.0 L of the solution.</em>

M = (no. of moles of solute)/(V of the solution (L)).

∴ M = (mass/molar mass)of C₁₂H₂₂O₁₁/(V of the solution (L)).

<em>∴ mass of C₁₂H₂₂O₁₁ = (M)(molar mass)(V of the solution (L)</em> = (1.0 M)((342.3 g/mol)/(0.10 L) = <em>34.23 g.</em>

5 0
4 years ago
Please explain moles concept​
larisa86 [58]

Answer:

A mole is the amount (10) of material containing 6.02214 × 10 raised to the power of 23 particles.

5 0
1 year ago
As a student , what can you do to help in preventing pollution in your community ?​
aliya0001 [1]

Answer: as a student , i will  do to help in preventing pollution in my  community :

Reduce the number of trips you take in your car.

Reduce or eliminate fireplace and wood stove use.

Avoid burning leaves, trash, and other materials.

Avoid using gas-powered lawn and garden equipment.

Using non-toxic or less toxic chemicals as cleaners, degreasers and other maintenance chemicals. Implementing water and energy conservation practices. Reusing materials such as drums and pallets rather than disposing of them as waste.

Store your household chemicals (including cleaning products, paints, fuel canisters, etc.) as far away as possible from the living space and, if possible, in metal cabinets. Do not store chemicals in areas where you spend most of the time. Also, do not store chemicals in open cabinets or shelves.

Use Public Transportation. Use your vehicle a lot less often. .

Drive Smart. .

Do Regular Car Check-Up. .

Keep Car Tires Properly Inflated. .

Buy Energy-Efficient Vehicles. .

Consider “going green” .

Plant a Garden. .

Use Low-VOC or Water-based Paints.

Avoid smoking indoors (but quitting smoking is the best answer for overall health).

Use craft supplies in well-ventilated areas.

Make sure your gas stove is well-ventilated.

Minimize clutter.

Remove carpeting if possible.

Use a dehumidifier and/or air conditioner to reduce moisture.

How can students help reduce pollution?

Help Recycling

The most obvious things to reuse are plastic, glass, metal, and paper or fabric (paper and organic fabric are made of the same component, cellulose, and are recycled in a similar way). The color-coded trash bins show where each of these components can be put to be recycled in a proper way.

REDUSE ,REUSE , RECYCLE

3 0
3 years ago
The heat of vaporization of water at the normal boiling point, 373.2 K, is 40.66 kJ/mol. The molar heat capacity of liquid water
Tatiana [17]

Answer:

\Delta _{vap}H(300.2K)=43,658\frac{J}{mol}=43.66\frac{kJ}{mol}

Explanation:

Hello!

In this case, according to the Kirchhoff's law for the enthalpy change, it is possible to compute the heat of vaporization at 300.2 K by considering the following thermodynamic route:

\Delta _{vap}H(300.2K)=Cp_{liq}(T_b-T\°)+\Delta _{vap}H\°+Cp_{vap}(T-T_B)

Whereas the first term stands for the effect of taking the liquid from 298.15 K to 373.15 K, the second term stands for the standard enthalpy of vaporization and the last term that of the vapor from the boiling point to 300.2 K; thus we plug in to obtain:

\Delta _{vap}H(300.2K)=75.37\frac{J}{mol*K} (373.2K-298.15K)+40,660\frac{J}{mol} +36.4\frac{J}{mol*K}(300.2K-373.2K)\\\\\Delta _{vap}H(300.2K)=43,658\frac{J}{mol}=43.66\frac{kJ}{mol}

Best regards!

6 0
3 years ago
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