When the direction of an object changes, what happens to its velocity?
1 answer:
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Answer:
<u> Power = 9.75 ×10^8</u>
Explanation:
- Power is rate of change of energy.
- Here gravitational energy is transferred to kinetic energy of water at a definite rate.
For one second 650m^3 of water flows out down to 150m oh depth.
So, the energy at a height of 150m is transformed to kinetic energy.
for a second,
650m^3 of water flows down ⇒ (1000kg/m^3 × 650m^3) = 6.5×10^5kg of warer flos down.
The total gravitational potential energy stored in water is
= <u>mass of water × height× gravity</u>
= 6.5 ×10^5 × 150 × 10 = 9.75 ×10^8
As it is transformed in a second it is also equal to <u>Power.</u>
Answer:
f = 5.3 Hz
Explanation:
To solve this problem, let's find the equation that describes the process, using Newton's second law
∑ F = ma
where the acceleration is
a =
B- W = m \frac{d^2 y}{dt^2 }
To solve this problem we create a change in the reference system, we place the zero at the equilibrium point
B = W
In this frame of reference, the variable y' when it is oscillating is positive and negative, therefore Newton's equation remains
B’= m
the thrust is given by the Archimedes relation
B = ρ_liquid g V_liquid
the volume is
V = π r² y'
we substitute
- ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }
this differential equation has a solution of type
y = A cos (wt + Ф)
where
w² = ρ_liquid g π r² /m
angular velocity and frequency are related
w = 2π f
we substitute
4π² f² = ρ_liquid g π r² / m
f =
calculate
f =
f = 5.3 Hz
Answer:
The electrical potential energy is 0.027 Joules.
Explanation:
The values from the question are
charge (q) =
Electric Field strength (E) =
Distance from source (d) = 0.030 m
Now the formula for the electrical potential energy (U) is given by
So now insert the values to find the answer
On further solving