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Harrizon [31]
3 years ago
7

If a balloon is heated, what happens to the volume of the air in the balloon if the pressure is constant?

Chemistry
1 answer:
MakcuM [25]3 years ago
4 0

Answer:

B. It increases.

Explanation:

  • We can use the general law of ideal gas: <em>PV = nRT.</em>

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R  is the general gas constant,

T is the temperature of the gas in K.

It is clear that, at constant P, the volume of the gas (V) is directly proportional to the temperature of the gas.

<em>V ∝ T.</em>

<em></em>

<em>So, If a balloon is heated, the volume of the air in the balloon if the pressure is constant:</em>

B. It increases.

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riadik2000 [5.3K]
Answer: 90 grams

0.5 molar of glucose means 0.5mole glucose for 1 liter of water. Since we want to made 1L of solution, then the amount of glucose needed is: 0.5mole/l x 1l= = 0.5mole

Glucose molecular weight is 180, then 0,5 mol of glucose is= 0.5mole x 180 grams/mole= 90 grams.
6 0
3 years ago
If 7.0 mol sample of a gas has a volume of 12.2 L, what would the volume be if the amount of gas was increased to 16.8 mol
Leviafan [203]

Answer:

V_{2} = 29.28\,L

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}

V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)

V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)

V_{2} = 29.28\,L

5 0
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What type of energy is stored for use at a later time? Bond energy Free energy Kinetic energy Potential energy
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Lapatulllka [165]
I got 134.91 but if you round it you’ll get 135
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The heating element of a hair dryer dissipates 1500 w when connected to a 180 v outlet. part a what is its resistance?
Sophie [7]

The resistance of the heating element is 21.61 Ω

Given

The power dissipated = 1500 W

Voltage = 180 V

We know that

Power = Voltage * Current

⇒ Power / Voltage = Current

⇒ 1500 W/180 V = Current

⇒ 8.33 A = Current

In order to calculate the resistance of the heating element. We Have to apply the formula

Power = (Current)^2 * Resistance

⇒ Resistance = Power / (Current)^2

⇒ Resistance = 1500 W/ (8.33) ^2

⇒ Resistance = 21.61 Ω

Hence the resistance of the heating element is 21.61 Ω

Learn more about resistance here: -

“ brainly.com/question/17330679  “

#SPJ4

5 0
2 years ago
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