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4 years ago

How does the use of simple machines affect force and distance when work is done?

Physics

1 answer:

bazaltina [42]4 years ago

8 0

Answer:

Explanation:

Machines simply make work easier to do. They increase the amount of force exerted on a body and also the distance through which the force is applied. Also, they can also change the direction through which force on them is applied in order to produce much more work.

Work done = force x distance

The input force in a machine is attenuated to yield even more force. This is the purpose of designing a simple machine. When the force increases, more work would be produce with our little effort applied on the body.

Work done is a function of the force applied on a body and the distance through which it moves.

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Why don't the two forces in Newton's third law cancel each other? They act in the same direction. They are different kinds of fo

pogonyaev

Answer:They act on different bodies

Explanation:

Newton's third law of motion states that for every action there is equal and opposite reaction i.e. action and reaction. Though action and reaction are equal they act in different bodies that is why they do not cancel out each other.

For example, a block of mass m placed over the table exerts a force of mg to the table while the table applies a Normal reaction of equal magnitude as of mg to the block of mass m.

5 0

3 years ago

Water flows with constant speed through a garden hose that goes up to 27.5 cm high. if the water pressure is 132kpa at the botto

sergejj [24]

Answer:

The pressure at the top of the step is 129.303 kilopascals.

Explanation:

From Hydrostatics we find that the pressure difference between extremes of the water column is defined by the following formula, which is a particular case of the Bernoulli's Principle ( $v_{bottom}\approx v_{top}$ ):

$p_{bottom}-p_{top} = \rho\cdot g\cdot \Delta h$ (1)

$p_{bottom}$ , $p_{top}$ - Total pressures at the bottom and at the top, measured in pascals.

$\rho$ - Density of the water, measured in kilograms per cubic meter.

$\Delta h$ - Height difference of the step, measured in meters.

If we know that $p_{bottom} = 132000\,Pa$ , $\rho = 1000\,\frac{kg}{m^{3}}$ , $g = 9.807\,\frac{m}{s^{2}}$ and $\Delta h = 0.275\,m$ , then the pressure at the top of the step is:

$p_{top} = p_{bottom}-\rho\cdot g\cdot \Delta h$

$p_{top} = 132000\,Pa-\left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.275\,m)$

$p_{top} = 129303.075\,Pa$

$p_{top} = 129.303\,kPa$

The pressure at the top of the step is 129.303 kilopascals.

6 0

3 years ago

Mutations can be transmitted to the next generation only if they are present in

emmainna [20.7K]

Answer:

The germline (the gametes)

Explanation:

Mutations are permanent changes in the DNA sequence. They can occur randomly, from mistakes during DNA replication, or as the result of external factors like UV radiation.

For these mutations to be passed on to the next generation, they must be present in the DNA of the gametes(i.e. the egg and sperm cells). This is because this is the DNA that goes on to make the offspring in the next generation following fertilisation.

If mutations are present in somatic cells (i.e. cells other than the gametes), they are not passed on to the next generation. For example, if someone gets mutations in their skin cells as a result of exposure to UV rays, this will not be passed on to their children.

7 0

3 years ago

a quarterback throws a football with angle of elevation 40degrees and speed 60ft/s. Find the horizontal and vertical components

pshichka [43]

<span>
the horizontal velocity would be equal to
Vh = sin (40) /60
= 0.74 * 60
= 44
</span>
the Vertical velocity would be equal to
<span>Vv = cos(40) * 60
=40</span>

4 0

3 years ago

in a hydraulic garage the small piston has a radius of 5 cm and the large piston has radius of 15 cm what force must be applied

viktelen [127]

The force applied to small piston = 2.2 x 10³ N

<h3>Further explanation</h3>

Given

a radius of 5 cm and 15 cm

weight 20000 N

Required

Force applied

Solution

Pascal Law :

F₁/A₁=F₂/A₂

A₁ = π.5²

A₂ = π.15²

F₁/ π.5² cm² = 20000/π.15² cm²

F₁ = 2222.22 N⇒2.2 x 10³ N

5 0

3 years ago