<h3>
Answer:</h3>
95.21 g/mol
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<h3>
Explanation:</h3>
<u>Step 1: Identify</u>
MgCl₂
<u>Step 2: Find Formula Weight</u>
[PT] Molar Mass of Mg - 24.31 g/mol
[PT] Molar Mass of Cl - 35.45 g/mol
Molar Mass of MgCl₂ - 24.31 + 2(35.45) = 95.21 g/mol
Answer:
D) The halogens tend to form 1+ ions.
Explanation:
A) Is correct because the atom gains an electron
B) Is correct because metals tends to lose electrons
C) Is correct because the atom loses an electron
D) Is incorrect because the halogens tends to gain electrones (1-)
E) Is correct because Nonmetals tend to form anions
Your first step is determining how many gram of KCl are in every mole of KCl. This can be done by simply looking at K and Cl's atomic mass on the Periodic Table. You add K's atomic mass (39.1g) with Cl's atomic mass (35.45g) to determine that the mass of one mole of KCl is 74.55g. Because you have 10 moles of KCl you multiply 74.55g by 10 to reach your answer of 745.5g.
Answer:
waste energy = 30 J
Explanation:
Given that.
Input energy = 100 J
Useful energy = 70 J
We need to find the amount of waste energy.
Waste energy = total energy - used energy
= 100 J - 70 J
= 30 J
Hence, 30 J of energy is waste energy.
Remember that a conjugate acid-base pair will differ only by one proton.
None of the options you listed are conjugate acid-base pairs as none of them differ only by one proton (or H⁺)
An example of a conjugate acid-base pair would be NH₃ and NH₄⁺NH₃ + H₂O --> NH₄⁺ + OH⁻NH3 is the base, and NH₄⁺ is the conjugate acid
