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LekaFEV [45]
4 years ago
10

The unit meters corresponds to what variable

Physics
1 answer:
Sati [7]4 years ago
7 0

Do you have any options? My guess would be distance but I could be wrong.

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What is the change in potential energy if the distance separating the electron and proton is increased to 1.0 nm?
Vlada [557]

Answer:

Ep=-2.3*10^{-19}J

Explanation:

The change in potential energy can be expressed as:

Ep=K.\frac{q1.q2}{r}

where K is a constant with a value of 9*10^{9}\frac{N.m^{2}}{C^{2}}, q1 and q2 are the charges of the proton and the electron and r is the distance between them.

The charge for the proton is +1.6*10^{-19}C and the charge for the electron is -1.6*10^{-19}C.

Converting r=1.0nm to m:

1.0nm*\frac{1*10^{-9}m}{1.0nm}=1*10^{-9}m

Replacing values:

Ep=9*10^{9}\frac{N.m^{2}}{C^{2}}.\frac{(+1.6*10^{-19}C).(-1.6*10^{-19}C)}{1*10^{-9}m}

Ep=-2.3*10^{-19}J

5 0
3 years ago
If the car’s speed decreases at a constant rate from 64 mi/h to 30 mi/h in 3.0 s, what is the magnitude of its acceleration, ass
mixas84 [53]

Answer:3.874 m/s^2

Explanation:

Given

Car speed decreases at a constant rate from 64 mi/h to 30 mi/h

in 3 sec

60mi/h \approx 26.8224m/s

34mi/h \approx 15.1994 m/s

we know acceleration is given by =\frac{velocity}{Time}

a=\frac{15.1994-26.8224}{3}

a=-3.874 m/s^2

negative indicates that it is stopping the car

Distance traveled

v^2-u^2=2as

\left ( 15.1994\right )^2-\left ( 26.8224\right )^2=2\left ( -3.874\right )s

s=\frac{488.419}{2\times 3.874}

s=63.038 m

7 0
3 years ago
Help please!!!!!!!!!!!!!!!!!!!!
Pavel [41]
Looks like you need to review through the lesson and take notes as it tells you in the lesson what each of these are.
8 0
4 years ago
Which is an example of an abiotic factor in a pound environment
zvonat [6]
A. The water

Biotic factors mean living this such as frogs, grasshoppers, snakes, etc.

Aboriginal factors means non-living such as water, temperature, sunlight, etc.
Abiotic factors are the non-living parts of the environment that have a major influence on living organisms which makes water an abiotic factor.

Hope this helped, if it did please like (if you want to :)
4 0
4 years ago
Read 2 more answers
A 10.0-kg animal is running at a rate of 3.0 m/s. What is the kinetic energy of the animal?
Ilya [14]
Kinetic energy is calculated by using formula:

Ek = 1/2*m*v^2

Now we replace values of mass and speed in this formula.

Ek = 1/2*10*3^2 = 45.0J

When you have a formula and all variable values are given in the text of question just replace variable values in equation and find the final value.
4 0
3 years ago
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