Answer:
4.5 M
Explanation:
70.0 ml was mixed in 3.00 M of Na2SO4
30.0 ml was mixed in 1.00 M of NACL
The first step is to convert 70 ml to liters
= 70/1000
= 0.07 liters
The formular for molarity is
moles/liters
The number of moles in Na2S04 can be calculated as follows
Let y represent the number of moles
3M= y moles/0.07
= 3×0.07
= 0.21 moles
Since Na2So4 has 2 moles of Na then the number of moles is
= 2×0.21
= 0.42 moles
Convert 30ml to liters
= 30/1000
= 0.03 liters
The number of moles in Nacl can be calculated as follows
Let y represent the number of moles
1M= y moles/0.03
= 1×0.03
= 0.03 moles
Since Nacl has 1 mole of Na then the number of moles is
= 1 × 0.03
= 0.03 moles
Therefore the final Na+ can be calculated as follows
Total moles = 0.03 moles + 0.42 moles
= 0.45 moles
Total liters= 0.07 liters + 0.03 liters
= 0.1 liters
Na+ = 0.45/0.1
= 4.5 M
Hence the final Na+ in the solution is 4.5 M
By studying seismic waves
Explanation:
Scientists discovered that the earth's outer core is liquid by simply studying seismic waves.
Seismic waves are elastic waves that have been used by geophysicists to study the earth's interior.
- Interior of the earth is inaccessible due to high pressure and temperature conditions therein.
- To study this part of the earth, an indirect method should be used.
- Seismic waves produced during an earthquake due to their permeating nature have been used to study the interior.
- Seismic P-waves can pass through any materials because they are longitudinal waves. They go through solids, liquids and gases.
- S-waves can only pass through solids and not fluids.
- On a seismograph, it was discovered that the S-waves were cut off in a part of the reading.
- The waves re-appeared after a distance.
- Since S-waves cannot pass through liquids, it has been hypothesized that the outer core is liquid.
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We have 6 moles of C (2*3=6), 14 moles of H (2*7=14) and 1 mol of O in 1 mol of <span>(C₃H₇)₂O:
Therefore:
1 mol of </span><span>(C₃H₇)₂O-------------6 moles of C
0.185 moles of </span><span>(C₃H₇)₂O------ x
x=(0.185 moles * 6 moles)/1 mole=1.11 moles
Answer: there are 1.11 moles of C in 0.185 moles of dipropyl ether
1 mol of C-----------------6.022*10²³ atoms
1.11 moles of C------------ x
x=(1.11 moles of C *6.022*10²³ atoms)/1 mole of C=6.68 *10²³ atoms
Answer: there are 6.68*10²³ atoms of C in 0.185 moles of dipropyl ether.
</span>
1 mole of <span>(C₃H₇)₂O-------------14 moles of H
0.185 moles of </span><span>(C₃H₇)₂O------ x
</span>
<span>x=(0.185 moles * 14 moles)/1 mole=2.59 moles
</span>
<span> there are 2.59 moles of H in 0.185 moles of dipropyl ether
1 mol -----------------------6.022*10²³ atoms
2.59 moles----------------- x
x=(2.59 moles * 6.022*10²³ atoms)/1 mol=1.56*10²⁴ atoms
Answer: there are </span><span>1.56*10²⁴ atoms in 0.185 moles of dipropyl ether.
</span>
<span>1 mol of <span>(C₃H₇)₂O-------------1 moles of C
0.185 moles of </span><span>(C₃H₇)--------- x</span>
x=(0.185 moles *1mol)/1 mol=0.185 moles
Answer: there are 0.185 moles of O in 0.185 moles of dipropyl ether.
</span>
A. 3
From 0 to 6, a solution is acidic. 7 is neutral and from 8 to 14.. is basic
