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Harrizon [31]
3 years ago
6

Water has a specific heat capacity nearly nine times that of iron. Suppose a 50-g pellet of iron at a temperature of 200∘C is dr

opped into 50 g of water at a temperature of 20∘C.
When the system reaches thermal equilibrium, its temperature will be
a. closer to 20∘C.
b. halfway between the two initial temperatures.
c. closer to 200∘C.
Physics
1 answer:
miv72 [106K]3 years ago
4 0

Answer:

a. closer to 20∘C

Explanation:

m_{p} = mass of pallet = 50 g = 0.050 kg

c_{p} = specific heat of pallet = specific heat of iron

T_{pi} = Initial temperature of pellet = 200 C

m_{w} = mass of water = 50 g = 0.050 kg

c_{w} = specific heat of water

T_{wi} = Initial temperature of water = 20 C

T_{e} = Final equilibrium temperature

Also given that

c_{w} = 9 c_{p}

Using conservation of energy

Energy gained by water = Energy lost by pellet

m_{w} c_{w} (T_{e} - T_{wi}) = m_{p} c_{p} (T_{pi} - T_{e})\\(0.050) (9) c_{p} (T_{e} - 20) = (0.050) c_{p} (200 - T_{e})\\ (9) (T_{e} - 20) =  (200 - T_{e})\\T_{e} = 38 C

hence the correct choice is

a. closer to 20∘C

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Therefore the torque exerted on it is 2.45*10^{-3}N\cdot m

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