Two solid balls (one larger, the other small) and a cylinder roll down a hill. Which has the greatest speed at the bottom and wh
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Answer:
The work done on the wagon is 37 joules.
Explanation:
Given that,
The force applied by Charlie to the right, F = 37.2 N
The force applied by Sara to the left, F' = 22.4 N
We need to find the work done on the wagon after it has moved 2.50 meters to the right. The net force acting on the wagon is :
Work done on the wagon is given by the product of net force and displacement. It is given by :
W = 37 Joules
So, the work done on the wagon is 37 joules. Hence, this is the required solution.
Answer:
1.41 m/s^2
Explanation:
First of all, let's convert the two speeds from km/h to m/s:
Now we find the centripetal acceleration which is given by
where
v = 12.8 m/s is the speed
r = 140 m is the radius of the curve
Substituting values, we find
we also have a tangential acceleration, which is given by
where
t = 17.0 s
Substituting values,
The two components of the acceleration are perpendicular to each other, so we can find the resultant acceleration by using Pythagorean theorem: