All categories

3 years ago

Whose atomic theory explains how atoms emit and absorb light

1 answer:

5 0

Darwin's atomic theory which states that atoms do not emit or absorb energy so far as they remain in allowable orbits or ground states.It also states that a spectra is produced when an electron moves to a lower energy level thereby releasing energy.

You might be interested in

A 3.0 \Omega Ω resistor is connected in parallel to a 6.0 \Omega Ω resistor, and the combination is connected in series with a 4

GarryVolchara [31]

Answer:

The power dissipated in the 3 Ω resistor is P= 5.3watts.

Explanation:

After combine the 3 and 6 Ω resistor in parallel, we have an 2 Ω and a 4 Ω resistor in series.

The resultating resistor is of Req=6Ω.

I= V/Req

I= 2A

the parallel resistors have a potential drop of Vparallel=4 volts.

I(3Ω) = Vparallel/R(3Ω)

I(3Ω)= 1.33A

P= I(3Ω)² * R(3Ω)

P= 5.3 Watts

7 0

3 years ago

A rectangular pane of glass is 91.1 cm wide and 155.9 cm long, and its area is equal to the length multiplied by the width. Usin

Kamila [148]

911.1×155.9 = 14,202.49
14,202.49 in 3 significant figures would be either 14,200 or 1.42×10^4

8 0

3 years ago

Read 2 more answers

A person on a ferry boat walks from one side of the ferry to the other. Their velocity is 1.5m/s[W] relative to the ferry. The f

Fittoniya [83]

The person's velocity relative to the shore is determined as 6.5 m/s.

<h3>Velocity of the person</h3>

The velocity of the person is calculated as follows;

V(p/f) = V(p) - V(f)

where;

V(p/f) is the velocity of the person relative to the ferry
V(p) is the velocity of the person
V(f) is velocity of the ferry

1.5 = V(p) - 5

V(p) = 6.5 m/s

Thus, the person's velocity relative to the shore is determined as 6.5 m/s.

Learn more about relative velocity here: brainly.com/question/17228388

#SPJ1

8 0

2 years ago

What is the frequency of a photon that has the same momentum as a neutron moving with a speed of 1.90 × 103 m/s?

Minchanka [31]

The mass of a neutron is:
$m=1.67 \cdot 10^{-27}kg$
Since we know its speed, we can calculate the neutron's momentum:
$p=mv=(1.67 \cdot 10^{-27}kg)(1.90 \cdot 10^3 m/s)=3.17 \cdot 10^{-24} kg m/s$

The problem says the photon has the same momentum of the neutron, p. The photon momentum is given by
$p= \frac{h}{\lambda}$
where h is the Planck constant, and $\lambda$ is the photon wavelength. If we re-arrange the equation and we use the momentum we found before, we can calculate the photon's wavelength:
$\lambda= \frac{h}{p}= \frac{6.6 \cdot 10^{-34}Js}{3.17 \cdot 10^{-24} kg m/s}=2.08 \cdot 10^{-10} m$

And since we know the photon travels at speed of light c, we can now calculate the photon frequency:
$f= \frac{c}{\lambda}= \frac{3 \cdot 10^8 m/s}{2.08 \cdot 10^{-10} m}= 1.44 \cdot 10^{18} Hz$

4 0

3 years ago

Two red blood cells each have a mass of 9.05×10−14 kg and carry a negative charge spread uniformly over their surfaces. The repu

belka [17]

Answer:

v = 330.7 m/s

Explanation:

Let say initially the speed of two blood cells is v and they are far apart from each other

when they come to the closest distance to each other then in that case the initial total kinetic energy of two blood cells will convert into electrostatic potential energy of the cells

So we can say

$\frac{1}{2}mv^2 + \frac{1}{2}mv^2 = \frac{kq_1q_2}{2r}$