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3 years ago

How many moles of oxygen atoms are on 4.7x1022 molecules of carbon dioxide?

Chemistry

1 answer:

scoundrel [369]3 years ago

3 0

Answer:

0.076

Explanation:

n=4.7×10^22/6.022×10^23

n=0.076mol

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An organic compound has the empirical formula C2H4O. what is the compound?

rosijanka [135]

Answer:

The correct answer is - butanoic acid

Explanation:

An empirical formula is the general formula or base formula that is the simplest positive integer ratio of atoms present in a compound. The empirical formula is specific to specific compounds or types of compounds.

Among the given options, the empirical formula C2H4O is butanoic acid as the molecular formula of butanoic acid is - C4H8O2 which is multiple of C2H4O. Other compounds have different than this empirical formula.

3 0

3 years ago

Why are properties of covalent compounds so diverse

faltersainse [42]

Answer:

The diversity of physical properties among covalent compounds is mainly because of widely varying intermolecular attractions. ... All of the atoms are covalently bonded to each other.

5 0

2 years ago

How many moles of ammonia can be formed from 4.0 mol H2

Bess [88]

Answer: 1. 2.7 moles of ammonia are formed

2. 12.0 moles of hydrogen are required

3. 2.0 moles of nitrogen are required

Explanation:

The balanced chemical equation is:

$N_2+3H_2\rightarrow 2NH_3$

According to stoichiometry:

3 moles of hydrogen form = 2 moles of ammonia

Thus 4.0 moles of hydrogen form = $\frac{2}{3}\times 4.0=2.7moles$ of ammonia

According to stoichiometry:

2 moles of ammonia are formed by = 3 moles of hydrogen

Thus 8.0 moles of ammonia are formed by = $\frac{3}{2}\times 8.0=12.0moles$ of hydrogen

According to stoichiometry:

3 moles of hydrogen react with = 1 mole of nitrogen

Thus 6.0 moles of hydrogen react with = $\frac{1}{3}\times 6.0=2.0moles$ of nitrogen

3 0

2 years ago

You have just isolated a new radioactive element. If you can determine its half-life, you will win the Nobel Prize in physics. Y

lbvjy [14]

Answer: 2.58 days

Explanation:

Expression for rate law for first order kinetics is given by:

$t=\frac{2.303}{k}\log\frac{a}{a-x}$

where,

k = rate constant = ?

t = age of sample = 6 days

a = initial amount of the reactant = 1 g

a - x = amount left after decay process = 0.2 g

a) to find the rate constant

$6=\frac{2.303}{k}\log\frac{1.0}{0.2}$

$k=\frac{2.303}{6}\log\frac{1.0}{0.2}$

$k=0.268days^{-1}$

b) for completion of half life:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

$t_{\frac{1}{2}}=\frac{0.693}{k}$

$t_{\frac{1}{2}}=\frac{0.693}{0.268}=2.58days$

The half life is 2.58 days

3 0

3 years ago

If there were an element above fluorine in the periodic table what phase would you expect it to be in (at room temp)?

AysviL [449]

If there were an element above fluorine, its state would be a gas. This is because fluorine is located in the non-metal section of the periodic table which can all be found as a gas at room temperature.

3 0

3 years ago