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Brrunno [24]
3 years ago
5

Light cannot escape the intense gravitational pull of a _____.

Physics
2 answers:
PSYCHO15rus [73]3 years ago
6 0
<span>Black hole, at a distance less than its event horizon.</span>
natima [27]3 years ago
3 0
Black hole 
hope it helped
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As the temperature of an object increases, the wavelength of the brightest light emitted _______
alexira [117]

Answer:

option (B) decreases

Explanation:

According to the Wein's displacement law, the minimum wavelength of the radiated emission is inversely proportional to the absolute temperature of the body which emits radiation.

\lambda_{m}\alpha \frac{1}{T}

Where, T is the absolute temperature of the body and λm is the minimum wavelength of heat radiated.

Here, as the temperature increases, the wavelength decreases.

4 0
3 years ago
Wave traveling at 330 m/sec has a wavelength of 4.3 meters. What is the frequency of this wave?
Rasek [7]

Answer:

76.74 Hz

Explanation:

Given:

Wave velocity ( v ) = 330 m / sec

wavelength ( λ ) = 4.3 m

We have to calculate Frequency ( f ):

We know:

v = λ / t [ f = 1 / t ]

v = λ f

= > f = v / λ

Putting values here we get:

= > f = 330 / 4.3 Hz

= > f = 3300 / 43 Hz

= > f = 76.74 Hz

Hence, frequency of sound is 76.74 Hz.

6 0
3 years ago
A boat of mass 225 kg drifts along a river at a speed of 21 m/s to the west. what impulse is required to decrease the speed of t
zzz [600]
The impulse required to decrease the speed of the boat is equal to the variation of momentum of the boat:
J=\Delta p=m \Delta v
where
m=225 kg is the mass of the boat
\Delta v=v_f-v_i=15 m/s-21 m/s=-6 m/s is the variation of velocity of the boat
By substituting the numbers into the first equation, we find the impulse:
J=m\Delta v=(225 kg)(-6 m/s)=-1350 N s
and the negative sign means the direction of the impulse is against the direction of motion of the boat.
8 0
4 years ago
Read 2 more answers
What’s the velocity of a ball falling with 100 joules of kinetic energy and a mass of 2 kilograms
ohaa [14]

Answer:

the velocity is 10 m/s

Explanation:

Using the expression for kinetic energy we have:

Ek=\frac{1}{2} *m*v^{2} \\\\Ek=100J\\m=2kg\\v=\sqrt{(2*100/2)}\\ v=10[m/s]

3 0
3 years ago
As Aubrey watches this merry-go-round for a total of 2 minutes, she notices the black horse pass by 15 times. What is the period
Hunter-Best [27]
Periodic time is the time taken for one complete oscillation by a body in circular motion. In this case the merry-go round takes 2 minutes to cover 15 complete oscillations. 2 Minutes = 120 seconds
Hence, 15 oscillations takes 120 secs
         thus 1 oscillation takes 120/15 = 8 seconds
therefore the period of the merry-go-round = 8 seconds
8 0
3 years ago
Read 2 more answers
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