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olya-2409 [2.1K]
3 years ago
8

Refer to the diagram to answer the question. Which part of the eye enables it to focus? A B C D E

Physics
1 answer:
Ilia_Sergeevich [38]3 years ago
8 0

Answer:

what are the A B C D E

Explanation:

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How man significant figures does the following value gave 43.023
Varvara68 [4.7K]

Answer:

It has 5 I hope this helps you

7 0
3 years ago
The electric flux through a square-shaped area of side 5 cm near a very large, thin, uniformly-charged sheet is found to be 3\ti
deff fn [24]

Answer:

Explanation:

Given

side of square shape a=5\ cm

Electric flux \phi =3\times 10^{-5}\ N.m^2/C

Permittivity of free space \epsilon_0=8.85\times 10^{-12} \frac{C^2}{N.m^2}

Flux is given by

\phi =EA\cos \theta

where E=electric field strength

A=area

\theta=Angle between Electric field and area vector

E=\frac{\phi }{A\cos (0)}

E=\frac{3\times 10^{-5}}{25\times 10^{-4}\times \cos(0)}

E=0.012\ N/C

and Electric field  by a uniformly charged sheet is given by

E=\frac{\sigma }{2\epsilon_0}

where \sigma=charge density

=\frac{\sigma }{\epsilon_0}

\sigma =0.012\times 8.85\times 10^{-12}

\sigma =2.12\times 10^{-13}\ C/m^2    

5 0
3 years ago
Why can you plant plants, but not water water?
Grace [21]

Answer:

Because water is water and its a liquid meanwhile plants are plants living things that you can move around.

Explanation:

3 0
2 years ago
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Oil _____.
timurjin [86]
Oil is made from buried remains of plants and animals.
6 0
3 years ago
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An ideal heat-engine is to be used in an environment where the ambient temperature is 23.5 °C. What should be the minimum temper
Digiron [165]

Answer:

The minimum temperature of the hot reservoir = 231.25 °C

Explanation:

η₁ = (1- T(c)/T(h)) × 100 ............. equation 1

Where η₁ = efficiency of the heat engine in percentage, T(c) = Temperature at which the low temperature reservoir operates, T(h)) =Temperature at which the high temperature reservoir operates.

Making T(h) the subject of the equation in equation 1

T(h) = T(c)/ {1-(η₁ /100)}

where η₁ = 41.2%, T(c) = 23.5 °C = 23.5 + 273 =296.5 K

∴T(h) = 296.5/{1-(41.2/100)}

 T(h) = 296.5/(1- 0.412)

 T(h) = 296.5/0.588

  T(h)  =504.25 K

Convert to temperature in Celsius

   T(h) = 504.25 - 273 =231.25 °C

The minimum temperature of the hot reservoir = 231.25 °C

 

 

3 0
3 years ago
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