A force on a particle depends on position such that f(x) = (3.00 n/m2)x 2 + (3.50 n/m)x for a particle constrained to move along
2 answers:
Answer:
Work done, W = 15 joules
Explanation:
It is given that,
The force acting on a particle depends on position such that,
Let W is the work done by this force on a particle that moves from x = 0.00 m to x = 2.00 m. The expression for work done is given by :
W = 15 Joules
So, the work done by this force on a particle is 15 joules. Hence, this is the required solution.
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Answer:
emf will also be 10 times less as compared to when it has fallen
Explanation:
We know, from faraday's law-
and
So, as the height increases the velocity with which it will cross the ring will also increase.
Given
Now, from
From equation a and b we see that velocity when dropped from is 10 times greater when height is 40
so, emf will also be 10 times less as compared to when it has fallen
Answer:
a. t = 1.43 s
b. d = 7.88 m
Explanation:
a. The time of flight can be found using the following equation:
Where:
: is the final height = -10 m
: is the initial height = 0
: is the initial speed in the vertical direction = 0
g: is the acceleration due to gravity = 9.81 m/s²
By solving the above equation for "t" we have:
Hence, the ball will hit the ground in 1.43 s.
b. The distance in the horizontal direction can be found as follows:
Where:
x₀: is the initial position in the horizontal direction = 0
a: is the acceleration in the horizontal direction = 0 (it is moving at constant speed)
Therefore, the ball will travel 7.88 m before it hits the ground.
I hope it helps you!