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AURORKA [14]
2 years ago
10

A star ending its life with a mass of four to eight times the Sun's mass is expected to collapse and then undergo a supernova ev

ent. In the remnant that is not carried away by the supernova explosion, protons and electrons combine to form a neutron star with approximately twice the mass of the Sun. Such a star can be thought of as a gigantic atomic nucleus. Assume r-aA1/3. If a star of mass 3.88 x 1030 kg is composed entirely of neutrons (mn 1.67 x 1027 kg), what would its radius be?
Physics
1 answer:
Zielflug [23.3K]2 years ago
8 0

Answer:

r = 16 Km

Explanation:

given  

m_n= 1.67 x 10^-27 Kg

M_star = 3.88 x 10^30 Kg  

A= M_star/m_n

A= 3.88*10^30/1.67 x 10^-27

A=2.28 *10^57  neutrons                           A = The number of neutrons  

we use the number of neutrons as a mass number because the star has only neutrons. = 1.2 x 10-15 m

r = r_o*A^1/3

r = 1.2*10^-15*2.28 *10^57^1/3

r = 16 Km

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slava [35]

Answer:

The alkaline earth metals (beryllium (Be), magnesium (Mg), calcium (Ca), strontium (Sr), barium (Ba), and radium (Ra)) are a group of chemical elements in the s-block of the periodic table with very similar properties: shiny. silvery-white. somewhat reactive metals at standard temperature and pressure.

5 0
3 years ago
The half-life of an anticancer drug is 170 days at 25 oC. Degradation follows the first-order kinetics. When the drug is stored
julsineya [31]

Answer:

1694 days

Explanation:

In first-order kinetics, the rate is proportional to the amount.

dA/dt = kA

For first-order kinetics, the rate k can be found using the half-life:

t₁,₂ = (ln 2) / k

In other words, the half-life is inversely proportional with the rate.

At the lower temperature, the rate is reduced to a third, so the half-life increases by a factor of 3.  Meaning that the new half-life is 170 × 3 = 510 days.

The "shelf life" is the time it takes to reduce the initial amount to 10%.  We can solve for this using the half-life equation.

A = A₀ (½)^(t / t₁,₂)

A₀/10 = A₀ (½)^(t / 510)

1/10 = (½)^(t / 510)

ln(1/10) = (t / 510) ln(½)

ln(10) = (t / 510) ln(2)

ln(10) / ln(2) = t / 510

t = 510 ln(10) / ln(2)

t ≈ 1694

5 0
3 years ago
An object with a mass of 4.91 kg rests on a plane inclined 42.34 ° from horizontal. What is the component of the weight force th
12345 [234]

the perpendicular component will be = Wy

Wy = w * cos 42.34 = 48.11 N x cos 42.34 = 35.54 N

3 0
1 year ago
A 190 g rock at 20°C is completely immersed in 600 g of water at 80°C. Which one of the following statements is true right after
Umnica [9.8K]

Rock is completely immersed in hot water. By the second law of thermodynamics, thermal energy or heat is transferred from substance with higher temperature to substance with lower temperature until they come to thermal equilibrium i.e. both at same temperature.

It is given here that rock is at 20°C which is at lower temperature than water at 80°C. ∴Heat or thermal energy flows from water to rock. So, right choice is-

A. The water gives the rock thermal energy and gets no thermal energy in return.

8 0
3 years ago
What is the SI unit of electric charge
shusha [124]

Answer:

The SI unit for electric chargeis the C (which is the abbreviation of Coulomb}

Explanation:

The SI unit for electric chargeis the Coulomb. The letter used is the C.

1 C = 1 As

4 0
3 years ago
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