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marysya [2.9K]
3 years ago
11

Terrrrrrrrrrrrrrrrrrrrrrrr?

Chemistry
2 answers:
FrozenT [24]3 years ago
6 0

what is your question?

velikii [3]3 years ago
6 0
Whats your question
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BF3 + Li2SO3 ---> B2(SO3)3 + LiF. What is the coefficient of lithium fluoride in the balanced chemical reaction? A. 1 B. 2 C.
uranmaximum [27]
The unbalanced equation is BF3 + Li2 SO3 --> B2 (SO3)3 + LiF, where the numbers to the right of the symbols are subscripts. The balanced equation is 2 BF3 + 3 Li2SO3 ---> B2 (SO3)3 + 6LiF. The numbers in front of every formula (compound) are the respective coefficients. You can check that the equation is balanced counting every element: There are 2B in the side of the reactants and 2B in the side of the products; there are 6F in the side of the reactants and 6F in the side of the products; there are 6 Li in the side of the reactants and 6 Li in the side of the products; and there are 3 SO3 in the side of the reactants and 3 SO3 in the side of the products. <span>So, the coefficient of the LiF is 6.</span>
3 0
3 years ago
Read 2 more answers
Is the following a chemical or physical
Usimov [2.4K]

Explanation:

  • Chemical .
  • As you can't get sodium or chloride back from sodium chloride.
  • Sodium chloride is a ionic compound so the bonding is too hard to break .

There are two types of reactions

  1. Physical
  2. Chemical
6 0
3 years ago
How many pounds of manganese are in 1.261 tons of Mn2O3?
Alina [70]

Answer:

2000pound

Explanation:

Manganese metal is produced from the manganese(III) oxide, Mn2O3, which is found in manganite, a manganese ore. The manganese is reduced from its +3 oxidation state in Mn2O3 to the zero oxidation state of the uncharged metal by reacting the Mn2O3 with a reducing agent such as aluminum or carbon. How many pounds of manganese are in 1.261 tons of Mn2O3? (1 ton = 2000 pounds)

About 40 different substances called organophosphorus compounds are registered in the United States as insecticides. They are considered less damaging to the environment than some other insecticides because they breakdown relatively rapidly in the environment. The first of these organophosphorus insecticides to be produced was tetraethyl pyrophosphate, TEPP, which is 33.11% carbon, 6.95% hydrogen, 38.59% oxygen, and 21.35% phosphorus. It has a molecular mass of 290.190.

4 0
2 years ago
If you have done 1.06 Lab :Gas laws please let me know !! Thanks &lt;3
Zielflug [23.3K]

Ideal gas law, Charles law, Boyle's law.

<u>Explanation:</u>

Gas laws:

Charles law: Volume of a gas is directly proportional to the temperature.

V∝T

Boyle's law : Pressure of a gas is inversely proportional to the volume of a gas at constant temperature.

PV= k

Ideal gas law is the combined law of Charles and Boyle's law, PV = nRT.

3 0
3 years ago
In a titration of 35.00 mL of 0.737 M H2SO4, __________ mL of a 0.827 M KOH solution is required for neutralization.
elena55 [62]

Answer:

In a titration of 35.00 mL of 0.737 M H₂SO₄, 62.4 mL of a 0.827 M KOH solution is required for neutralization.

Explanation:

The balanced reaction is

H₂SO₄  +  2 KOH  ⇒  2 H₂O  +  K₂SO₄

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction)  1 mole of H₂SO₄ is neutralized with 2 moles of KOH.

The molarity M being the number of moles of solute that are dissolved in a given volume, expressed as:

Molarity=\frac{number of moles}{volume}

in units of \frac{moles}{liter}

then the number of moles can be calculated as:

number of moles= molarity* volume

You have acid H₂SO₄

  • 35.00 mL= 0.035 L (being 1,000 mL= 1 L)
  • Molarity=  0.737 M

Then:

number of moles= 0.737 M* 0.035 L

number of moles= 0.0258

So you must neutralize 0.0258 moles of H₂SO₄. Now you can apply the following rule of three: if by stoichiometry 1 mole of H₂SO₄ are neutralized with 2 moles of KOH, 0.0258 moles of H₂SO₄ are neutralized with how many moles of KOH?

moles of KOH=\frac{0.0258moles of H_{2} SO_{4}*2 moles of KOH }{1mole of H_{2} SO_{4}}

moles of KOH= 0.0516

Then 0.0516 moles of KOH are needed. So you know:

  • Molarity= 0.827 M
  • number of moles= 0.0516
  • volume=?

Replacing in the definition of molarity:

0.827 M=\frac{0.0516 moles}{volume}

Solving:

volume=\frac{0.0516 moles}{0.827 M}

volume=0.0624 L= 62.4 mL

<u><em>In a titration of 35.00 mL of 0.737 M H₂SO₄, 62.4 mL of a 0.827 M KOH solution is required for neutralization.</em></u>

4 0
3 years ago
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