Kenny, who has a mass of 15 kg, slides down a friction-less slide that is 3.2 m tall. Cartman, who has a mass of 85 kg, slides d
own the same slide. A. What speed does Kenny reach at the bottom of the slide?
B. What speed does Cartman reach the bottom of the slide?
C. Kyle slides down the same slide. What speed does Kyle reach at the bottom of the slide? Explain.
<u>a).</u> Kenny's potential energy at the top becomes kinetic energy at the bottom.
(M G H) = 1/2 (M V²)
Divide each side by 'M': G H = 1/2 V²
Multiply each side by 2: 2 G H = V²
Take the square root of each side: V = √(G H)
= √(9.8 x 3.2) = <em><u>5.6 m/s .</u></em>
<u>b).</u> Notice in the solution for a). that each side of the equation was divided by 'M'. The answer didn't depend on Kenny's mass, and it doesn't depend on Cartman's mass either. Cartman and Kenny are both moving at the same speed when they reach the bottom.
<u>c).</u> Notice in the solution for a). that each side of the equation was divided by 'M'. The answer didn't depend on Kenny's mass. It didn't depend on Cartman's mass either, and it doesn't depend on Kyle's mass either, either. Each of them is moving at the same speed when he reaches the bottom. The same also applies to girls as well, too.
The net force of the object is equal to the force applied minus the force of friction. Fnet = ma = F - Ff 12 kg x 0.2 m/s² = 15 N - Ff The value of Ff is 12.6 N. This force is equal to the product of the normal force which is equal to the weight in horizontal surface and the coefficient of friction. Ff = 12.6 N = k(12 kg)(9.81 m/s²) The value of k is equal to 0.107.